D=event that chip selected is defective
d=event that chip selected is NOT defective
Four possible scenarios for the first two selections:
P(DDD)=15/100*14/99*13/98=13/4620
P(DdD)=15/100*85/99*14/98=17/924
P(dDD)=85/100*15/99*14/99=17/924
P(ddD)=85/100*84/99*15/98=17/154
Probability of third selection being defective is the sum of all cases,
P(XXD)=P(DDD)+P(DdD)+P(dDD)+P(ddD)
=3/20
The largest number that 8c could be is -15
Answer:
<h3>
90</h3>
Step-by-step explanation:
The middle number of three consecutive integers is thhe mean of the others, so it is one third of the sum of three consecutive integers
267:3 = <u>89 </u> - the middle number
so:
89 - 1 = 88 - the smallest number
89 + 1 =<u> 90</u> - the largest integer
Answer:
A. 3:30.
Step-by-step explanation:
180 is 90+90 so that would put it in 3:30.
The final solution is y=-5/3x-10