Answer:
B.O(n).
Explanation:
Since the time complexity of visiting a node is O(1) in iterative implementation.So the time complexity of visiting every single node in binary tree is O(n).We can use level order traversal of a binary tree using a queue.Which can visit every node in O(n) time.Level order traversal do it in a single loop without doing any extra traversal.
Answer:
U.S. Bureau of Labor Statistics.
Explanation:
The Bureau of Labor Statistics is a unit of the United States Department of Labor assigned with the task of fact-finding in the field of labor and statistics for the government. The agency helps measure the labor activity in the market and evaluates all forms of activity regarding labor conditions for the government.
This agency also functions or serves as the principal agency for the United States Federal Statistical System. It not only collects information or data but also helps spread the said information to the government. It also published a biennial handbook describing various occupations.
Answer: it is very easy to work with programs such as audacity, they are real game changers. Also, they are very helpful for editing and recording audio. They could make audacity’s auto tune more beginner friendly
Sorry to answer you so late but that would be truth because that is the first rule of science which is what thermodynamics depends in.
The first law of thermodynamics is a type of law of conservation but with thermodynamics systems.
So, in gogle I found this: "The law of conservation of energy states that the total energy of an isolated system is constant; energy can be transformed from one form to another, but cannot be created or destroyed."
Like I said, sorry to reply so late but I hope this helped! =)
Answer:
Java code is given below
Explanation:
import java.util.Random;
class Die{
private int sides;
public Die(){
sides = 6;
}
public Die(int s){
sides = s;
}
public int Roll(){
Random r = new Random();
return r.nextInt(6)+1;
}
}
class DieRoll{
public static void main(String[] args) {
Die die = new Die();
int arr[] = new int[6];
for(int i=0; i<6; i++)
arr[i] = 0;
for(int i=0; i<100; i++){
int r = die.Roll();
arr[r-1]++;
}
for(int i=0; i<6; i++)
System.out.println((i+1)+" was rolled "+arr[i]+" times.");
}
}
