Given : f(x)= 3|x-2| -5
f(x) is translated 3 units down and 4 units to the left
If any function is translated down then we subtract the units at the end
If any function is translated left then we add the units with x inside the absolute sign
f(x)= 3|x-2| -5
f(x) is translated 3 units down
subtract 3 at the end, so f(x) becomes
f(x)= 3|x-2| -5 -3
f(x) is translated 4 units to the left
Add 4 with x inside the absolute sign, f(x) becomes
f(x)= 3|x-2 + 4| -5 -3
We simplify it and replace f(x) by g(x)
g(x) = 3|x + 2| - 8
a= 3, h = -2 , k = -8
Answer: 5.14 cu in
Step-by-step explanation:
1/2 (π × d) + d, where d is the diameter of the semi
Perimeter = 1/2 (3.14 x 2) + 2
= 1/2 * 6.28 + 2
= 3.14 + 2
Answer:
y =0
Step-by-step explanation:
From the equation;
8³ × 8⁻⁵×8^y = 8⁻²= 1/8²
From the laws of indices;
aⁿ×aⁿ = a^2n
Therefore;
8³ × 8⁻⁵×8^y = 8^(3+-5+y)
8^(-2+y) = 8^-2 ; but the bases are the same and thus the exponents are the same;
-2 + y = -2
y = 0
First integer = x
Second integer = x + 2
Third integer = x + 4
Since four times the first integer equals six more than the product of two and the third integer.
4x = 6 + 2(x + 4)
4x = 6 + 2x + 8
2x = 14
x = 7.
Hence,
First integer = x = 7
Second integer = x + 2 = 7 + 2 = 9
Third integer = x + 4 = 7 + 4 = 11.
hope this helps
