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2 years ago

PLEASE ANSWER!

Mathematics

1 answer:

butalik [34]2 years ago

5 0

We just plug in, simplify, and solve.

x/2 + 3x - y

8/2 + 3(8) - 2

4 + 24 - 2

28 - 2

Option C should be your answer.

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How to solve 2(x+y)^2-9(x+y)-5

Aliun [14]

Answer:

2(x + y)² - 9( x + y ) -5 = 0

⇒2(x + y)² - 10 (x+y) +1(x+y) -5 = 0

⇒2(x+y)(x + y - 5 ) + 1(x + y -5 ) = 0

taking (x + y -5 ) common ,

⇒(x + y -5 )[2(x + y) + 1] =0

⇒(x + y -5)(2x + 2y +1) =0

hope , you got this

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3 years ago

Lucia is making invisibility potions. Each potion requires 2 eyes of newt. How many invisibility potions can Lucia make with 16

Oksana_A [137]

8.

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3 years ago

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A Web site defines a regular polygon as “a polygon with all angles the same measure.” Is this definition valid?

IceJOKER [234]

B. Yes Becuase a square has all equal sides

4 0

2 years ago

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Show that 5x^2 + 2x - 3 < 0 can be written in the form | x + 1/5 | < 4/5

Sliva [168]

Step-by-step explanation:

First let solve the inequality

$5 {x}^{2} + 2x - 3 < 0$

Factor by grouping

$5 {x}^{2} + 5x - 3x - 3 < 0$

$5x(x + 1) - 3(x + 1)$

So the factor are

$(5x - 3)(x + 1)$

So the factor are

$x = \frac{3}{5}$

and

$x = - 1$

Solutions to a quadratic can be represented by a absolute value equation because remeber quadratics

creates 2 roots and/or double roots.

The inequality

$|x - b| < c$

works as

b is the midpoint between 2 roots. And c is the

$|x + b| = c$

We know that the midpoint between both roots is-1/5.

$|x - ( - \frac{1}{5} )| < c$

$|x + \frac{1}{5} | < c$

Let use roots 3/5

$| \frac{3}{5} + \frac{1}{5} | = \frac{4}{5}$

-1 works as well.

$| - 1 + \frac{1}{5} | = | - \frac{4}{5} | = \frac{4}{5}$

So the absolute value equation is

$|x + \frac{1}{5} | < \frac{4}{5}$

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2 years ago

Which expression is equivalent to (4g3h2k4)3

Agata [3.3K]

72 ghk4

See explanation

6 0

3 years ago