The given question is incomplete. The complete question is:
Omar rented a truck for one day. There was a base fee of $17.95, and there was an additional charge of 98 cents for each mile driven. Omar had to pay $23 when he returned the truck. For how many mile did he drive the truck?
Answer: Omar drove the truck for 5.15 miles
Step-by-step explanation:
Base fee = 17.95 $
Additional charge per mile = 98 cents = 0.98 $ ( 100cents = 1$)
Now Omar payed = 22 $
Let the miles he travelled = x
Now , 
Solvimg for x :
Thus Omar drove the truck for 5.15 miles
Answer:
(fog)(x)=f(g(x))=2(3x+2)−1=6x+4−1=6x+3=3(2x+1)
9514 1404 393
Answer:
3.0
Step-by-step explanation:
The angle, its opposite side, and the hypotenuse are given. Then the relevant trig relation is ...
Sin = Opposite/Hypotenuse
sin(21°) = x/8.3 . . . . . . . . . . . . . . . . . . use the given values
x = 8.3·sin(21°) ≈ 8.3×0.3584 . . . . . . multiply by 8.3
x ≈ 3.0
Answer:
u didn't show anything so I can't help u. can u show a picture or something
Answer:
17 ± sqrt(337)
-----------------------
2
Step-by-step explanation:
Let a = shorter leg
b= longer leg = a+7
c = hypotenuse = 2a-5
We can use the Pythagorean theorem
a^2+b^2 = c^2
a^2 + (a+7)^2 = (2a-5)^2
(a+7)^2 = a^2 +7a +7a+49 = a^2 +14a +49
(2a-5)^2 = 2a*2a -10a -10a +25 = 4a^2 -20a +25
Substituting these into the equation
a^2 + (a^2 +14a +49) = (4a^2 -20a +25)
Combine like terms
2a^2 +14a +49 = 4a^2 -20a +25
Subtracting 2a^2 from each side
2a^2 -2a^2 +14a +49 = 4a^2-2a^2 -20a +25
+14a +49 = 2a^2 -20a +25
Subtract 14a from each side
-14a+14a +49 = 2a^2 -20a -14a+25
+49 = 2a^2 -34a +25
Subtract 49 from each side
49-49 = 2a^2 -34a +25-49
0 = 2a^2 -34a -24
Divide each side by 2
0/2 = 2/2a^2 -34/2a -24/2
0 = a^2 -17a -12
Using the quadratic formula
a=1 b= -17 c = -12
17 ±sqrt( (-17)^2 - 4(1)(-12))
----------------------------------
2(1)
17 ± sqrt(337)
-----------------------
2
