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o-na [289]
3 years ago
11

Select all expressions that are equal to 3⋅3⋅3⋅3⋅3

Mathematics
2 answers:
Veseljchak [2.6K]3 years ago
8 0
The answer to this would be B, C, and E
notka56 [123]3 years ago
5 0
B and c are the correct answers

because they all add up to 243

but a, d, and e don’t.
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Using the following information = Universal set = {2,3,4,5,6,7,8,9,12,13,14,16,20,22,56). Subset A = {9,12,13,20,22,56); Subset
Cloud [144]

\dfrac{2}{5},\dfrac{13}{15},\dfrac{3}{5},\dfrac{1}{5},\dfrac{1}{5}

step-by-step explanation:

The intersection of two sets A and B, denoted by A ∩ B, is the set containing all elements of A that also belong to B.

The union (denoted by ∪) of a collection of sets is the set of all elements in the collection.

P(s) of a set s is defined as ratio of number of elements in s to the number of elements in universal set

given Universalset=\{\text{2,3,4,5,6,7,8,9,12,13,14,16,20,22,56}\}

given A=\{9,12,13,20,22,56\} and H=\{4,5,8,9,16,22\}

and C=\{1,4,20,22,56\}

For Question A:

A∩H=\{9,12,13,20,22,56\} ∩ \{4,5,8,9,16,22\}

=\{9,22}\}

(A∩H)∪C=\{9,22}\} ∪ C=\{1,4,20,22,56\}=\{1,4,9,20,22,56\}

p((A∩H)∪C)=\frac{6}{15}=\frac{2}{5}

For Question B:

H∩C=\{4,22\}

p(H∩C)'=\frac{15-2}{15}=\frac{13}{15}

For Question C:

p(H)'=\frac{15-6}{15}=\frac{3}{5}

For Question D:

C\H=\{1,20,56\}

p(C\H)=\frac{3}{15}=\frac{1}{5}

For Question E:

A\C=\{9,12,13\}

p(A\C)=\frac{3}{15}=\frac{1}{5}

7 0
3 years ago
The area of ABED is 49 square units. Given AGequals9 units and ACequals10 ​units, what fraction of the area of ACIG is represent
stiks02 [169]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

A=b^{2}

where b is the length side of the square

we have

A=49\ units^2

substitute

49=b^{2}

b=7\ units

therefore

AB=BE=ED=AD=7\ units

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

A=(AC)(AG)

substitute the given values

A=(9)(10)=90\ units^2

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

A=(DE)(DG)

we have

DE=7\ units

DG=AG-AD=9-7=2\ units

substitute

A=(7)(2)=14\ units^2

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

A=(EF)(CF)

we have

EF=AC-AB=10-7=3\ units

CF=BE=7\ units

substitute

A=(3)(7)=21\ units^2

step 5

sum the shaded areas

14+21=35\ units^2

step 6

Divide the area of  of the shaded region by the area of ACIG

\frac{35}{90}

Simplify

Divide by 5 both numerator and denominator

\frac{7}{18}

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

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3 years ago
The basic model of pure competition reviewed in this chapter finds that in the long run all firms in a purely competitive indust
marissa [1.9K]

Answer:

Companies must strive to improve their products and services within the framework of healthy competition.

Step-by-step explanation:

The competition is a situation of companies that compete in a requested market or demanding the same product or service. This implies that companies must strive to improve the balance of normal earnings.

creating new products or new solutions of lower cost. In this sense, if companies can innovate, they can obtain economic gains in the short term, and increase their profits.

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What is the volume, in cubic units, of a pyramid of height 8 and a
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A 1800 is the answer to this question
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What is the equation of the line that passes through (4,-1) and (-2,3)
vladimir1956 [14]

Answer: y-6 = 0.5 (x-8)

Step-by-step explanation:

y − y1 = m(x − x1)

The equation is useful when we know:

one point on the line: (x1,y1)

and the slope of the line: m,

and want to find other points on the line.

Have a play with it first (move the point, try different slopes):

8 0
3 years ago
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