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2 years ago

6

Find the number of complex roots, the possible number of real roots and the possible rational roots of the polynomial function.

Then, solve for all roots.
x^3+2x^2+3x+6=0

1 answer:

Feliz [49]2 years ago

6 0

Answer:

the answer is 69

Step-by-step explanation:

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Calculate the average of 7,081 and 8,890.

ASHA 777 [7]

Do you mean add are subtract
i will glad to help in comments
if you awnser

7 0

2 years ago

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Simplify: log81/8 + 2log2/3 - 3log 3/2 +log 3/4

MissTica

Answer:

0.

Step-by-step explanation:

Using the laws of logarithms:

log81/8 + 2log2/3 - 3log 3/2 + log 3/4

= log 81/8 + log (2/3)^2 - log (3/2)^3 + log 3/4

= log 81/8 + log 4/9 - log 27/8 + log 3/4

= log 81/8 + log 4/9 - (log 27/8 - log 3/4)

= log (81/8 * 4/9) - log (27/8 * 4/3)

= log 9/2 - log 9/2

= 0.

5 0

2 years ago

A degree 4 polynomial P(x) with integer coefficients has zeros 5 i and 3, with 3 being a zero of multiplicity 2. Moreover, the c

Sergio039 [100]

Multiplicity is how many times the root repeats

roots r1 and r2 of a polynomial factor to

(x-r1)(x-r2)

so 3 multiplicty 2 means (x-3)^2 is in the factorization of that polynomial

also, for a polynomial with real coefients, if a+bi is a roots, a-bi is also a root

5i is a root, therefor -5i is a root as well

roots are

(x-5i)(x+5i)(x-3)^2

if we expand

x^4-6x^3+34x^2-150x+225

the polynomial is

f(x)=x^4-6x^3+34x^2-150x+225

6 0

2 years ago

Help me please fvfbvtne d f vrgvbv

Ivenika [448]

Answer:

<h2>Height (h) =54.6mm</h2>

Step-by-step explanation:

Given :

Base (b) = 7.7mm

Area (a) = 210.21mm^2

Height (h) = ?

$Area = \frac{base\times height}{2} \\\\210.21= \frac{7.7\times h}{2} \\\\210.21\times2 = 7.7\times h\\\\420.42 = 7.7 h\\\\\frac{420.42}{7.7}=\frac{7.7h}{7.7}\\\\54.6 =h\\\\h=54.6$

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2 years ago

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Ummm i don’t understand these I just started can someone help

bixtya [17]

so for question 2 find the area of the rectangle first:

$15 \times 19 = 285$

then you find the area of the triangles:

$15 \times 13 = 195 \\ 195 \div 2 = 97.5$

$15 \times 11 = 165 \\ 165 \div 2 = 82.5$

Add up all the answers:

$285 + 97.5 + 82.5 = 465$

and for question 3, part A, you just find the area of the 2 boxes and multiply:

$5 \times 5 = 25 \\ 25 \times 2 = 50$

$2 \times 5 = 10 \\ 10 \times 4 = 40$

$40 + 50 = 90$

so the surface area of the box is 90 square inches therefore the paint covered 90 square inches. For part B, just add up the length of the thick black lines:

$5 + 5 + 5 + 5 + 2 + 5 + 5 + 5 + 5 + 5 + 5 + 2 + 5 + 5 = 64$

How these helped have a good day

8 0

2 years ago