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alexandr1967 [171]

2 years ago

7

What is the percent decrease from 10 to 3

1 answer:

iragen [17]2 years ago

3 0

10 is the old value and 3 is the new value. In this case we have a negative change (decrease) of -70 percent because the new value is greater than the old value. The answer is -70 percent.

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First, identify what the question is asking for.

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2 years ago

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ZanzabumX [31]

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2 years ago

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Which is a solution to (x – 3)(x + 9) = –27?<br><br> x = –9<br> x = –3<br> x = 0<br> x = 6

likoan [24]

Answer:

x = 0

Step-by-step explanation:

Since the product is not equal zero, we need to multiply both parenthesis first:

$(x-3)(x+9) =-27$

$x*x+x*9+(-3)*x+(-3)*9=27$

$x^2+9x-3x-27=27$

$x^2+6x-27=27$

Add 27 from both sides:

$x^2+6x-27+27=-27+27$

$x^2-6x=0$

Factor $x$ out:

$x(x+6)=0$

Apply the zero product:

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We can conclude that the correct answer is x = 0.

7 0

2 years ago

The point P(2k, k) is equidistant from A(-2, 4) and B (7,-5).<br>Find the value of k.<br>

mario62 [17]

Answer:

k = 3

Step-by-step explanation:

Using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = A (- 2, 4 ) and (x₂, y₂ ) = P (2k, k)

AP = $\sqrt{(2k+2)^2+(k-4)^2}$

Repeat

with (x₁, y₁ ) = B (7, - 5) and P = (2k, k)

BP = $\sqrt{(2k-7)^2+(k+5)^2}$

Given that AP = BP, then

$\sqrt{(2k+2)^2+(k-4)^2}$ = $\sqrt{(2k-7)^2+(k+5)^2}$

Square both sides

(2k + 2)² + (k - 4)² = (2k - 7)² + (k + 5)² ← expand factors on both sides

4k² + 8k + 4 + k² - 8k + 16 = 4k² - 28k + 49 + k² + 10k + 25

Simplify both sides by collecting like terms

5k² + 20 = 5k² - 18k + 74 ( subtract 5k² from both sides )

20 = - 18k + 74 ( subtract 74 from both sides )

- 54 = - 18k ( divide both sides by - 18 )

k = 3

7 0

3 years ago