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tankabanditka [31]
3 years ago
9

Name two ordered pairs that are located exactly six units from (2, -3).

Mathematics
2 answers:
horsena [70]3 years ago
6 0
(8,-3)
(2,3)

Hope it helps
Phantasy [73]3 years ago
5 0
Exactly six units from:

Def'n: Add or subtract 6 to either "x" or "y" in (x,y) = (2, -3) 
         P.S. (BTW, there are many more ways that are a lot harder to find two orders pairs six units from (2, -3). These are only the easiest.)

1. (2, -3 + 6) = (2, 3)
2. (2, -3 - 6) = (2, -9)
3. (2 + 6, -3) = (8, -3)
4. (2 - 6, -3) = (-4, -3)

Pick from these four. :3



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Step-by-step explanation:

f(x)=g(x)-1 since was shifted down 1 unit                                        x^3-1

f(x)=g(x)+1 would have been a shift up of 1 unit                             x^3+1

f(x)=g(x-1) shifted right 1 unit                                                            (x-1)^3

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Anyways the answer is f(x)=x^3-1

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A man earns $3580 per month and spend 65% of it. How much does he save every month?
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3 0
3 years ago
|3x-7|-7=x solve the equation for all values of x
romanna [79]

The solutions to the given equation containing absolute value term |3x-7| - 7 = x are 0 and 7.

<h3>What are the solutions to the given equation?</h3>

Given the equation in question;

|3x-7| - 7 = x

First, add 7 to both sides.

|3x-7| - 7 + 7 = x + 7

|3x-7|  = x + 7

Next, remove the absolute value term, this creates a ± on the right side of the question.

|3x-7|  = x + 7

3x-7  = ±( x + 7 )

The complete solution is the result of both the negative and positive portions of the solution.

For the first solution, use the positive of ±.

3x-7  = ( x + 7 )

3x - 7  =  x + 7  

3x - x = 7 + 7

2x = 14

x - 14/2

x = 7

For the second solution, use the negative of ±.

3x-7  = -( x + 7 )

3x-7  = -x - 7

3x + x = -7 + 7

4x = 0

x = 0/4

x = 0

Therefore, the solutions to the given equation containing absolute value term |3x-7| - 7 = x are 0 and 7.

Learn to solve more equation involving absolute value term here: brainly.com/question/28635030

#SPJ1

4 0
1 year ago
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