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Sophie [7]
4 years ago
7

What is 9 plus 10 anyone lol

Mathematics
2 answers:
snow_lady [41]4 years ago
6 0

Answer:

19

Step-by-step explanation:

10 + 9 =19

AVprozaik [17]4 years ago
5 0

Answer: its 19 . lol

Step-by-step explanation:

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The function g(x) =2^x.The function f(x) =2^x+k and k<0
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Answer:  D. f(x) is k units below g(x)

Step-by-step explanation:

We're comparing for example g(x)=2^x and f(x)=2^x -1.  They're identical except the latter is one unit below the former.  

4 0
3 years ago
The top of an ice cream cone had a 2.25-inch diameter. What is its circumference?
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Pi is simply the ratio of the circumference to the diamater, what that means is<span>π=<span>Cd</span></span>(C is circumference, d is diameter) or, likewise<span>πd=C</span>So the circumference for your ice-cream cone is simply<span>πd=3.14∗2.25=7.065=C</span>So the circumference is 7.065 inches.
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kaheart [24]

Answer:

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Step-by-step explanation:

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Tara noticed that the tape she was using to wrap packages was 2 centimeters wide. How many meters wide was the tape?
Vikentia [17]
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3 years ago
How many equivalence relations are there on the set 1, 2, 3]?
Alex787 [66]

Answer:

We need to find how many number of equivalence relations are on the set {1,2,3}

A relation is an equivalence relation if it is reflexive, transitive and symmetric.

equivalence relation R on {1,2,3}

1.For reflexive, it must contain (1,1),(2,2),(3,3)

2.For transitive, it must satisfy: if (x,y)∈R then (y,x)∈R

3. For symmetric, it must satisfy: if (x,y)∈R,(y,z)∈R then (x,z)∈R

Since (1,1),(2,2),(3,3) must be there is R, (1,2),(2,1),(2,3),(3,2),(1,3),(3,1). By symmetry,

we just need to count the number of ways in which we can use the pairs (1,2),(2,3),(1,3) to construct equivalence relations.

This is because if (1,2) is in the relation then (2,1) must be there in the relation.

the relation will be an equivalence relation if we use none of these pairs (1,2),(2,3),(1,3) . There is only one such relation: {(1,1),(2,2),(3,3)}

we can have three possible equivalence relations:

{(1,1),(2,2),(3,3),(1,2),(2,1)}

{(1,1),(2,2),(3,3),(1,3),(3,1)}

{(1,1),(2,2),(3,3),(2,3),(3,2)}

6 0
4 years ago
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