Answer:
Isosceles trapezoid
Step-by-step explanation:
The figure will look like one large triangle on the outside and four smaller triangles on the inside. you are only concerned with the inside triangle that is pointing to the line FH. Since XY and FH are parallel and the distance between FX and YH are equivalent (the midpoints of each side should be the same for all three sides of the larger triangle) the shape FXYH is an isosceles trapezoid.
Simply plug in x = 4 in to the function
f(4) = 1/3 * 4
f(4) = 4/3
-3 (4x-5y+6)+8x-9= -12x+15y-18+8x-9= -4x+15y-27
