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3 years ago

Relative maxima and relative minima are called relative_____. Hint: first 2 letters are ex

Mathematics

2 answers:

Blababa [14]3 years ago

7 0

Relative minima extreme

Mama L [17]3 years ago

3 0

Relative maxima and relative minima extrema

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Answer The Expression. 55−63+20 1/4 ÷ 43 1/4

Diano4ka-milaya [45]

Answer:

-7.53179190751

Step-by-step explanation:

(55-63)+((20 1/4)/(43 1/4))=

-8+0.46820809248= -7.53179190751

5 0

3 years ago

During swim practice, an Olympic swimmer is required to complete three swimming intervals, in this order: warm-up freestyle, spr

Aleksandr-060686 [28]

Answer:

Step-by-step explanation:

I'm not sure if the warm up speed is less than the cool down speed. If it is different than how I did it you just need to swap their positions on the y axis, so the "lumps" or whatever you want to call the shapes will be in opposite positions. The middle one will stay the same because it is the fastest and in between the two happening. Also let me know if you can't read any of the labels

7 0

4 years ago

Read 2 more answers

Find the area of the trapezoidal cross-section of the irrigation canal shown below. Your answer will be in terms of h, w, and θ.

miskamm [114]

[w + (h/tan θ)] × h

<h3>Further explanation</h3>

We aim is to find the area of the trapezoidal cross-section of the irrigation canal.

The formula for the area of the trapezoid is $\boxed{\boxed{ \ Area = \frac{1}{2} \times (a + b) \times h \ }}$

a & b = parallel sides
h = height

We assume the lower side is $\boxed{ \ a = w \ }$ and the upper side is b = x + w + x or $\boxed{ \ b = w + 2x \ }$ . See the attached picture.

In the right triangles located on the left and right of the trapezoid, we calculate the value of x based on trigonometric ratios namely tan of theta.

$\boxed{ \ tan \ \theta = \frac{opposite}{adjacent} \ }$

$\boxed{ \ tan \ \theta = \frac{h}{x} \ }$

$\boxed{ \ x = \frac{h}{tan \ \theta} \ }$

Substitute the equation of x to $\boxed{ \ b = w + 2x \ }.$

We get $\boxed{ \ b = w + \frac{2h}{tan \ \theta} \ }$

Finally all components are complete and can be substituted into a formula to calculate the area of a trapezoid.

$\circ \ \boxed{a = w}\\ \circ \ \boxed{ \ b = w + \frac{2h}{tan \ \theta} \ }\\\circ \ and \ h$

$\boxed{ \ Area = \frac{1}{2} \times (w + w + \frac{2h}{tan \ \theta}) \times h \ }$

$\boxed{ \ Area = \frac{1}{2} \times (2w + \frac{2h}{tan \ \theta}) \times h \ }$

$\boxed{ \ Area = \frac{1}{2} \times 2(w + \frac{h}{tan \ \theta}) \times h \ }$

Hence, the area of the trapezoidal cross-section of the irrigation canal is $\boxed{\boxed{ \ Area = (w + \frac{h}{tan \ \theta}) \times h \ }}$

<h3>Learn more</h3>

Find out the area of parallelogram brainly.com/question/4459688
The order of rotational symmetry of rhombus brainly.com/question/4228574
Find out the coordinates of the image of a point after the triangle is rotated 270° about the origin brainly.com/question/7437053

Keywords: the trapezoidal, cross-section of the irrigation canal, the area, the answer will be in terms of h, w, and θ, trigonometric ratios, tan, opposite, adjacent, height, sides

3 0

4 years ago

Read 2 more answers

List the perfect squares between 100 and 500 that are even numbers

katen-ka-za [31]

$10^2=100 \\.................\\\ 11^2=121 \\ 12^2=144 \\ 13^2=169 \\ 14^2=196 \\ 15^2=225 \\ 16^2=256 \\ 17^2=289 \\ 18^2=324 \\ 19^2=361 \\ 20^2=400 \\ 21^2=441 \\ 22^2=484 \\................\\23^2=529$