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galina1969 [7]
3 years ago
8

Helppp meee

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
8 0

Answer:

1. A

2. B

Step-by-step explanation:

I = Prt where I = interest, P = Principal amt, r = interest rate/100, T = time taken

I = Prt

I = 3600 × 5/100 × 4

I = 720

From I = Prt,

t =  \frac{i}{pr}  \\ t =  \frac{96 \times 100}{800 \times 4}  \\ t = 3

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a coach requires the athletes on a team to run a time, t, of a 9 minute mile or faster. which graph represents this requirement
Vladimir [108]

C is the correct answer


4 0
3 years ago
What does the quotiant 35/x represent?
Bumek [7]
When 35 ÷ 7, the quotient would be 5, while 35 would be called the dividend, and 7, the divisor. I hope this helps
5 0
3 years ago
Select equivalent or nonequivalent for each pair of expressions
wel

Answer:

i think the answer is a as well <3

have a great day!

also wdym by i smell pennies??

6 0
3 years ago
Directions: Find the indicated trigonometric ratio as a fraction in simplest form. 1. Sin L =
Rainbow [258]

Answer:

\sin L = 0.60

tan\ N = 1.33

\cos L = 0.80

\sin N = 0.80

Step-by-step explanation:

Given

See attachment

From the attachment, we have:

MN = 6

LN = 10

First, we need to calculate length LM,

Using Pythagoras theorem:

LN^2 = MN^2 + LM^2

10^2 = 6^2 + LM^2

100 = 36 + LM^2

Collect Like Terms

LM^2 = 100 - 36

LM^2 = 64

LM = 8

Solving (a): \sin L

\sin L = \frac{Opposite}{Hypotenuse}

\sin L = \frac{MN}{LN}

Substitute values for MN and LN

\sin L = \frac{6}{10}

\sin L = 0.60

Solving (b): tan\ N

tan\ N = \frac{Opposite}{Adjacent}

tan\ N = \frac{LM}{MN}

Substitute values for LM and MN

tan\ N = \frac{8}{6}

tan\ N = 1.33

Solving (c): \cos L

\cos L = \frac{Adjacent}{Hypotenuse}

\cos L = \frac{LM}{LN}

Substitute values for LN and LM

\cos L = \frac{8}{10}

\cos L = 0.80

Solving (d): \sin N

\sin N = \frac{Opposite}{Hypotenuse}

\sin N = \frac{LM}{LN}

Substitute values for LM and LN

\sin N = \frac{8}{10}

\sin N = 0.80

7 0
3 years ago
What is the area of this trapezoid?
Sonbull [250]
Find the area of the square first
Area = Length x Width
Area = 12 x 9
Area = 108

Find the area of the right triangles
Area = 1/2(Length x Base)
Area = 1/2(9 x 2)
Area = 1/2(18)
Area = 9
Since there is 2 triangles multiply by 2
9 x 2 = 18

Now add
108 + 18 = 126
126 is your area
8 0
3 years ago
Read 2 more answers
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