Step-by-step explanation:
there are 4 suit with 13 cards each
- 3
distribute each bracket, multiplying the terms in the bracket by the value outside the bracket.
= 3g + 15 - 3g - 18 → ( collect like terms)
=(3g - 3g) + (15 - 18) = 0 + ( - 3) = - 3
That would be a / 3b^2
(re call that 1 /a^-1 = a)
<u>Answer:</u>

<u>Step-by-step explanation:</u>
32a^3 + 12a^2
To factorize this, start by taking the common variable out. As we have two powers for the same variable a, we can take the smaller power of a as a common to get like shown below:
32a^3 + 12a^2
a^2 (32a + 12)
Now when you have taken the variable as a common, try and take out a common number from the coefficient of a as well:
a^2 (32a + 12)
4a^2 (8a + 3)
So, the fully factored form of 32a^3 + 12a^2 is 4a^2 (8a + 3).
Given that the sides of the acute triangle are as follows:
21 cm
x cm
2x cm
Stated that 21 cm is one of the shorter sides of the triangle2x is greater than x, so it follows that 2x MUST be the longest side
For acute triangles, the longest side must be less than the sum of the 2 shorter sides
Therefore, 2x < x + 21cm
2x – x < 21cm
x < 21cm
If x < 21cm, then 2x < 42cm
Therefore, the longest possible length for the longest side is 42cm