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2 years ago

Can someone answer this question please answer it correctly if it’s corect I will mark you brainliest

Mathematics

1 answer:

erica [24]2 years ago

5 0

Answer:

dependent

Step-by-step explanation:

Maggie picks a card. Now there are only 3 cards left to choose from. Say she picked the yellow card first. Now on the second pick she wanted to get the yellow card. She can't because it is gone. The second draw depends on what happened on the first.

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Which of these is not an equation?

timurjin [86]

Answer:

Step-by-step explanation:

an equation always shows that sum is equal

in this case 1825026 will subtract 17 and the remainder will be used to find A

3 0

2 years ago

Find the total area for the regular pyramid. T. A. =

Allisa [31]

The total area is:
A = Ab + Al
Where,
Ab: base area
Al: lateral area
We have then:
For the base area:
Ab = (2) * (2)
Ab = 4 units ^ 2
For the lateral area:
Al = (4) * (1/2) * (2) * (root ((1) ^ 2 + (3) ^ 2))
Al = (4) * (root (1 + 9))
Al = 4raiz (10) units ^ 2
Total area:
A = 4 + 4raiz (10)
Answer:
A = 4 + 4raiz (10)

7 0

3 years ago

Read 2 more answers

Put these numbers in order from greatest to least. 1 6/8,-10/25,-18/25,1

goldenfox [79]

$\textsf{Hey there!}$

$\textsf{Put these numbers in order from GREATEST to LEAST}$

$\bullet{\mathsf{ \ 1\dfrac{6}{8}}}$

$\bullet\mathsf{\ -\dfrac{10}{25}}$

$\bullet{\mathsf{\ -\dfrac{18}{25}}}$

$\bullet{\textsf{ 1}}$

$\star\textsf{ We know that fractions, decimals, negatives are BELOW 0 (on the left}$ $\textsf{of 0)}$

$\star\textsf{ \& we also know that positives and real numbers is/are ABOVE 0 (to the right}$ $\textsf{of 0)}$

$\textsf{Now we can answer your question}$

$\blacksquare \ \mathsf{1\dfrac{6}{8} = \dfrac{14}{8} = 1.75}$

$\blacksquare\ \mathsf{-\dfrac{10}{25} = -0.40}$

$\blacksquare\ \mathsf{- \dfrac{18}{25} = -0.72}$

$\blacksquare \ \mathsf{1 = 1}$

$\textsf{Look carefully at the stuff converted to the decimal or regular number \& }$ $\textsf{you will have your answer from \underline{greatest} to \underline{least}}$