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3 years ago

Find the area of the circle that contains the sector described below. Round to the nearest tenth, if necessary.

Mathematics

1 answer:

Elis [28]3 years ago

6 0

Answer:

The area of the circle is 2520 cm²

Step-by-step explanation:

The area of an arc is given by the following formula:

arc area = pi*r²(angle/360)

In this case we have the area and the angle and we want to find r, so we have:

210 = pi*r²*(30/360)

210 = pi*r²*(1/12)

210*12 = pi*r²

pi*r² = 210*12

r² = 2520/pi

r = sqrt(2520/pi)

r = 28.3221

The area of the circle that has this arc is given by:

area = pi*r²

area = pi*(28.3221)² = 2520 cm²

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Because 7.7^2 equals 60,

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3 years ago

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Calcula el RIQ de las temperaturas en las Ciudades de Kansas, Misouri las temperaturas: 23,25,28,28,32,33,35 y en Paradise, Mich

sasho [114]

Respuesta:

Kansas, Misuri = 8

Paradise, Michigan = 3

Explicación paso a paso:

El rango intercuartílico (IQR) = Q3 - Q1

Q3 = 3/4 (n + 1) th término

n = número de muestras

Q1 = 1/4 (n + 1) th término

Kansas Misuri:

23,25,28,28,32,33,35

Datos pedidos: 23, 25, 28, 28, 32, 33, 35

n = 7

Q1 = 1/4 * 8 = 2do trimestre = 25

Q3 = 3/4 * 8 = 6. ° tem = 33

Q1 = 33 - 25 = 8

Paradise, Michigan:

16,24,26,26,26,27,28

Datos pedidos: 16,24,26,26,26,27,28

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2 years ago

A spinner numbered 1 through 12 is spun. Find the probability that

anastassius [24]

Answer:

$\dfrac{1}{6}$

Step-by-step explanation:

Let A be the event of getting an odd number.

P(A) be the probability of getting an odd number.

Total odd numbers here are 6 i.e. $\{1,3,5,7,9,11\}$

Here, total numbers in the game are 12 i.e $\{1,2,3,....,12\}$ .

Formula for probability of an event E can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

$P(A) = \dfrac{6}{12}\\\Rightarrow \dfrac{1}{2}$

Let B be the event of getting 11.

P(B) be the probability of getting 11.

Total number of possible cases is 1.

$P(B) = \dfrac{1}{12}$

$P(A \cap B)$ is the probability that we get 11 and an odd number.

Possible number of cases = 1

$P(A\cap B) = \dfrac{1}{12}$

P(B/A) is the probability that we get an 11 given that it is an odd number.

$P(B/A) = \dfrac{P(A \cap B)}{P(A)}\\\Rightarrow \dfrac{\dfrac{1}{12}}{\dfrac{1}{2}}\\\Rightarrow \dfrac{1}{6}$

Hence, P(B/A) = $\dfrac{1}{6}$

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3 years ago

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Answer:

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