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Serggg [28]
3 years ago
9

Ruby is visiting San Francisco. From her hotel she walks 4 blocks west and 3 blocks north to a coffee shop. Then she walks 6 blo

cks east and 2 blocks north to a museum. Where is the museum in relation to her hotel?
Mathematics
1 answer:
lara [203]3 years ago
5 0
This should make it easier for you: http://prntscr.com/iea135
You might be interested in
Cot^2x csc^2x + 2 csc^2x –cot^2 = 2
kow [346]

Answer:

x = π/2 + πk

Step-by-step explanation:

cot² x csc² x + 2 csc² x − cot² x = 2

Multiply both sides by sin² x:

cot² x + 2 − cos² x = 2 sin² x

Add cos² x to both sides:

cot² x + 2 = 2 sin² x + cos² x

Pythagorean identity:

cot² x + 2 = sin² x + 1

Subtract 1 from both sides:

cot² x + 1 = sin² x

Pythagorean identity:

csc² x = sin² x

Multiply both sides by sin² x:

1 = sin⁴ x

Take the fourth root:

sin x = ±1

Solve for x:

x = π/2 + 2πk, 3π/2 + 2πk

Which simplifies to:

x = π/2 + πk

4 0
4 years ago
$22.00+$14.00= <br> answer this
Zigmanuir [339]

Answer:

$36

Step-by-step explanation:

22+14=36

6 0
3 years ago
Tabitha received $2,200 from her aunt as a birthday gift. She decided to put the money in an account to save for college. The ac
arsen [322]

3225.36

Step-by-step explanation:

8 0
4 years ago
What is the end behavior of the graph of the polynomial function f(x) = –x5 + 9x4 – 18x3?
Oksanka [162]

Answer:

As x approaches ∞, y approaches -∞

As x approaches -∞, y approaches ∞

Step-by-step explanation:

f(x) = -x^5 + 9x^4 - 18x^3

F(x) is a fifth degree (odd function ) with negative leading coefficient

If exponent is odd and leading coefficient is negative then end behavior is

As x approaches ∞, y approaches -∞

As you go on the right , f(x) goes down

As x approaches -∞, y approaches ∞

As you go on the left , f(x) goes up

7 0
3 years ago
Read 2 more answers
Use the diagram to find the measure of arc. AB and CD and the diameters of the circle F
dybincka [34]

Answer:

11). m(\widehat{DE}) = 90°

12). m(\widehat{AEC}) = 212°  

Step-by-step explanation:

A circle F with AB and CD are the diameters has been given in the figure attached.

11). Since, m(\widehat{AB}) = 180°

    and m(\widehat{AB})=m(\widehat{AD})+m(\widehat{DE})+m(\widehat{BE})

    Therefore, m(\widehat{AD})+m(\widehat{DE})+m(\widehat{BE}) = 180°

    32° + m(\widehat{DE}) + 58° = 180°

    m(\widehat{DE}) = 180° - 90°

                = 90°

12. Since, m(\widehat{AD})=m(\widehat{BC}) = 32°

                 m(\widehat{AEC}) = m(\widehat{AB})+m(\widehat{BC})

                                = 180° + 32°

                                = 212°

7 0
3 years ago
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