Given the equation (x−13)2+y2=64, identify the center and radius. Do not enter any spaces when typing your answers.
1 answer:
Answer:
centre = (13,0)
radius = 8
Step-by-step explanation:
The standard equation of the circle is
(x-x0)^2 + (y-y0)^2 = r^2 ...............(1)
where
(x0,y0) is the centre,
r is the radius.
For
(x-13)^2 + y^2 = 64 ..............(2)
we rewrite (2)
(x-13)^2 + (y-0)^2 = 8^2 ...............(3)
and compare (3) with (1)
to identify
x0 = 13, y0 = 0, and r = 8
Therefore
centre = (13,0)
radius = 8
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