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3 years ago

Given the equation (x−13)2+y2=64, identify the center and radius. Do not enter any spaces when typing your answers.

Mathematics

1 answer:

Darya [45]3 years ago

3 0

Answer:

centre = (13,0)

radius = 8

Step-by-step explanation:

The standard equation of the circle is

(x-x0)^2 + (y-y0)^2 = r^2 ...............(1)

where

(x0,y0) is the centre,

r is the radius.

For

(x-13)^2 + y^2 = 64 ..............(2)

we rewrite (2)

(x-13)^2 + (y-0)^2 = 8^2 ...............(3)

and compare (3) with (1)

to identify

x0 = 13, y0 = 0, and r = 8

Therefore

centre = (13,0)

radius = 8

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vaieri [72.5K]

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We are given that

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3 years ago

The value of y varies directly with x. When y = 75, 7 = 1. What is the value of y when x is 272

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3 years ago

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Answer:

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3 years ago

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WITCHER [35]

Answer: 8.3 ft

Step-by-step explanation:

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