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RUDIKE [14]
2 years ago
13

Help with this question pls

Mathematics
1 answer:
GrogVix [38]2 years ago
4 0

Answer:

B .75

Step-by-step explanation:

hope this helped <3

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What does it mean to be a 'solution' to a function?
serg [7]
A number is a solution when it fits within the range of answers that the function generates.
8 0
3 years ago
6. A prism has bases that are equilateral triangles with sides lengths of 10 inches and a length of 30 inches.
eimsori [14]

Answer:

The volume of the prism is 1,299\ in^{3}

Step-by-step explanation:

we know that

The volume of the prism is equal to

V=BL

where

B is the area of the triangular base

L is the length of the prism

we have

L=30\ in

<em>Find the area of the base B</em>

The area of a equilateral triangle is equal to

B=\frac{1}{2}(10)^{2} sin(60\°)

B=25\sqrt{3}\ in^{2}

substitute

V=(25\sqrt{3})(30)=1,299\ in^{3}

8 0
3 years ago
If h = 9 units and r = 5 units, then what is the volume of the cone shown above?
dexar [7]

Answer:

Answer = 235.5

Step-by-step explanation:

Cone volume formula is V = 1/3 * pi * r^2 * h

V = 1/3 * 3.14 * 5^2 * 9

V = 235.5

6 0
3 years ago
A solid lies between planes perpendicular to the​ x-axis at x = -2 and x = 2. The​ cross-sections perpendicular to the​ x-axis b
icang [17]

Answer:

V = 128π/3 vu

Step-by-step explanation:

we have that: f(x)₁ = √(4 - x²);  f(x)₂ = -√(4 - x²)

knowing that the volume of a solid is  V=πR²h, where R² (f(x)₁-f(x)₂) and h=dx, then

dV=π(√(4 - x²)+√(4 - x²))²dx;  =π(2√(4 - x²))²dx ⇒

dV= 4π(4-x²)dx , Integrating in both sides

∫dv=4π∫(4-x²)dx , we take ∫(4-x²)dx and we solve

4∫dx-∫x²dx = 4x-(x³/3) evaluated -2≤x≤2 or too 2 (0≤x≤2) , also

∫dv=8π∫(4-x²)dx evaluated 0≤x≤2

V=8π(4x-(x³/3)) = 8π(4.2-(2³/3)) = 8π(8-(8/3)) =(8π/3)(24-8) ⇒

V = 128π/3 vu

8 0
3 years ago
The shown quadrilateral is a rectangle. If AB is 10 what is the length of DC?
kipiarov [429]
The answer is:

A. 10

This is because segment AB is parallel to segment DC, meaning they are the same length.

Hope this helps!
7 0
3 years ago
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