Answer:
a) r = 0.974
b) Critical value = 0.602
Step-by-step explanation:
Given - Two separate tests are designed to measure a student's ability to solve problems. Several students are randomly selected to take both test and the results are give below
Test A | 64 48 51 59 60 43 41 42 35 50 45
Test B | 91 68 80 92 91 67 65 67 56 78 71
To find - (a) What is the value of the linear coefficient r ?
(b) Assuming a 0.05 level of significance, what is the critical value ?
Proof -
A)
r = 0.974
B)
Critical Values for the Correlation Coefficient
n alpha = .05 alpha = .01
4 0.95 0.99
5 0.878 0.959
6 0.811 0.917
7 0.754 0.875
8 0.707 0.834
9 0.666 0.798
10 0.632 0.765
11 0.602 0.735
12 0.576 0.708
13 0.553 0.684
14 0.532 0.661
So,
Critical r = 0.602 for n = 11 and alpha = 0.05
He would earn $30 for 45 minutes.
Example:
60min=$40/hr
1min =$40/$60/hr
45min=$40/$60*45
$30 for 45min
Answer:476
Step-by-step explanation:
if you multiply 14 times 17 times 4 it equals 952 but if you divide it it equals 476
It would probably be 1 and 3/8 yards of string left because if he cut 5/8 yards of the string it would be a subject of subtraction, so if you would subtract that amount from 2 yards, the answer would be 1 and 3/8 yards of string left, hope this helps, good luck