(9t + 1) + 7(1 + 9t)<br><br> Complete the missing expressions!!

find the lenght of the poster board is 2 feet and the width is 1 whats the serea of the board of the poster

rusak2 [61]

2 square feet is the answer

8 0

3 years ago

(2,?) is on the line x + 3 = y. Find the other half of the coordinate.

Brut [27]

Sub in 2 for x and solve for y

x + 3 = y
2 + 3 = y
5 = y

so ur points are : (2,5)

4 0

3 years ago

Read 2 more answers

Which numbers are solutions to the inequality x < −4, using the replacement set {−10, −4.3, −4, −3.9, 2}?

GREYUIT [131]

On a number line, with the negative numbers on the left and the positive number on the right

the smaller the number, the farther it is to the left
so if you plot them on the number line
-10 is less than -4 because it is to the left of -4

so which make the statement true

what numbers are less than -4
-10 is to the left so this is an answer A

-4.3 is to the left so this is also an answer B

-3.9 is greater than becasue it is to the right so this is not answer C

2 is positive and to the right so it is not answer D

the correct answers are A and B

5 0

3 years ago

A manufacturer produces 400 units when the market price is $10 per unit and produces 600 units when the market price is $12 per

AVprozaik [17]

Answer:

your answer is $1,022 that is the answer

4 0

3 years ago

Last year it was found that on average it took students 20 minutes to fill out the forms required for graduation. This year the

Darina [25.2K]

Answer:

$t=\frac{18.5-20}{\frac{5.2}{\sqrt{22}}}=-1.35$

$p_v =P(t_{21}$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we FAIL to reject the null hypothesis, and the actual true mean for the time is not significantly less than 20 minutes at 5% of significance.

Step-by-step explanation:

Data given and notation

$\bar X=18.5$ represent the sample mean

$s=5.2$ represent the standard deviation for the sample

$n=22$ sample size

$\mu_o =20$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the mean for the new forms take less time to complete than the older forms, the system of hypothesis would be:

Null hypothesis: $\mu \geq 20$

Alternative hypothesis: $\mu < 20$

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{18.5-20}{\frac{5.2}{\sqrt{22}}}=-1.35$

Now we need to find the degrees of freedom for the t distirbution given by:

$df=n-1=22-1=21$

What do you conclude?

Compute the p-value

Since is a one left tailed test the p value would be:

$p_v =P(t_{21}$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we FAIL to reject the null hypothesis, and the actual true mean for the time is not significantly less than 20 minutes at 5% of significance.

7 0

3 years ago

(9t + 1) + 7(1 + 9t) Complete the missing expressions!!