which level are u on now?
Explanation:
1L=1000mL
1dm³=1L
1dm³=1000cm³
29.84ml-29.00ml=0.84ml
Density=mass(g)/volume(cm³)
=6.6g/(0.84cm³)
=?
Answer:
The concentration after 115 seconds is 0.0496 M
Explanation:
Applying integrated rate law for a first-order reaction, we will have;
![[A]_t = [A]_0e^{-kt}](https://tex.z-dn.net/?f=%5BA%5D_t%20%3D%20%5BA%5D_0e%5E%7B-kt%7D)
where;
![[A]_t](https://tex.z-dn.net/?f=%5BA%5D_t)
is the concentration at a time t
![[A]_0](https://tex.z-dn.net/?f=%5BA%5D_0)
is the initial concentration
k is the rate constant for the reaction
t is the given time
Given;
= 0.05 M
k = 6.2 x 10⁻⁵ mol L⁻¹s⁻¹
t = 115 seconds
Substitute these values and solve for
![[A]_t = [A]_0e^{-kt} = (0.05)*e^{-(6.2X10^{-5}*115)}\\\\](https://tex.z-dn.net/?f=%5BA%5D_t%20%3D%20%5BA%5D_0e%5E%7B-kt%7D%20%3D%20%280.05%29%2Ae%5E%7B-%286.2X10%5E%7B-5%7D%2A115%29%7D%5C%5C%5C%5C)
![[A]_t = (0.05)(0.9929) =0.0496 M](https://tex.z-dn.net/?f=%5BA%5D_t%20%3D%20%280.05%29%280.9929%29%20%3D0.0496%20M)
Therefore, the concentration after 115 seconds is 0.0496 M
The atom with the electron configuration has completely filled shells and will ordinarily not react with another atom.
<h3>Electronic configurations</h3>
Atoms with completely filled shells are said to be stable and will ordinarily not react with another atom irrespective of the number of valence electrons.
The S and P orbitals in the electron configuration have been completely filled. Only atoms with partially filled shells readily react with other atoms with partially filled shells.
More on electron configurations can be found here: brainly.com/question/14283892
#SPJ1
