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3 years ago

Write the standard equation for the circle.

2 answers:

7 0

The standard form of a circle is:

(x-h)^2+(y-k)^2=r^2, where r=radius and (h,k) is the center of the circle.

We are told that r=6 and the center is (10,-6) so

(x-10)^2+(y+6)^2=36

nekit [7.7K]3 years ago

5 0

Answer:- C. $(x-10)^2+(y+6)^2=36$

The standard equation for a circle is $(x-a)^2+(y-b)^2=r^2$ , where r is the radius and (a,b)= center of the circle such that a= abscissa and b= ordinate of center.

Given:- Center of circle=(10, –6) , radius r=6

Here abscissa of center a=10

ordinate of center b= -6

Substitute values of a, b and r in the standard equation of circle, we get

$(x-10)^2+(y-(-6))^2=6^2\\\Rightarrow(x-10)^2+(y+6)^2=36$

⇒ C is the correct answer.

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Describe the expression (4x÷2)-9y

sertanlavr [38]

<span>(4x ÷ 2) - 9y is difference of two terms.</span>

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3 years ago

In ΔABC, point M is the midpoint of side AB and point D is the midpoint of segment MC. Prove that the area of ΔADC= the area of

Anna11 [10]

A line segment from a vertex to the midpoint of the opposite side is a "median". A median divides the area of the triangle in half, as it divides the base in half without changing the altitude.
AAMC is half AABC. AADC is half AAMC, so is 1/4 of AABC. (By the formula for area of a triangle.)
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3 years ago

Two ballpoint pens are selected at random from a box that contains 3 blue pens, 2 red pens, and 3 green pens. If X is the number

Flauer [41]

Answer:

a) f(x,y) = $\frac{\binom{3}{x}\binom{2}{y}\binom{3}{2-x-y}}{\binom{8}{2}}$ ; x = 0, 1 , 2; y = 0, 1 , 2; 0 ≤ x+y ≥ 2

b) = $\frac{9}{14}$

Step-by-step explanation:

joint probability is a function that characterizes the distribution of a random variable. If X and Y be two random variables then the joint probability will be P(X = x, Y=y)

Given Data,

X = The number of blue Pens

Y = The number of red Pens

possible outcomes(X, Y) are (0, 0), (0, 1), (1, 0), (1, 1), (0, 2), (2,0)

Please refer fig. also

total number ways of selecting any 2 pens = $\binom{8}{2}$ = $\frac{8!}{2! 6!}$ =28

f(x,y) = $\frac{\binom{3}{x}\binom{2}{y}\binom{3}{2-x-y}}{\binom{8}{2}}$ ; x = 0, 1 , 2; y = 0, 1 , 2; 0 ≤ x+y ≥ 2

P(X,Y)∈A = P(X + Y ≤ 1)

= P(0,0) + P(1,0) + P(0,1)

= $\frac{3}{28}$ + $\frac{3}{14}$ + $\frac{9}{28}$

= $\frac{9}{14}$

4 0

4 years ago

How to solve it in quadratic functions

natita [175]

Answer:

x = 2

x = -3/2 or -1.5

Step-by-step explanation:

For this, I would use the "slip and slide" method. LOL I know the name is cheesy, but that's what my teacher called it!

First, you "slip" the coefficent of the leading term (2) to the constant, and multiply.

The equation becomes:

x² - x - 6(2) = 0

x² - x - 12 = 0

Then, you factor this out by looking at the second and third terms. You're looking for 2 factors of -12 that would add up to -1 ( the coefficent of the second term).

Automatically, think of 3 and 4, because the difference between them is 1.

The factors must be (x-4) and (x+3) because they multiple to -12, and add up to -1.

This step is extremely important! Lol I used to forget it a lot, but make sure you divide the constant in each factor by the original number you "slipped".

It would become (x-(4/2))(x+3/2) = (x-2)(x+3/2)

With (x+3/2), you don't want to leave it as a fraction or decimal. It's equivalent to (2x+3). However, the informal form is easier to identify the value of x.

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3 years ago

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MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

154

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3 years ago