Question

Write the standard equation for the circle.

Answer 1

The standard form of a circle is:

(x-h)^2+(y-k)^2=r^2, where r=radius and (h,k) is the center of the circle.

We are told that r=6 and the center is (10,-6) so

(x-10)^2+(y+6)^2=36

Answer 2

Answer:- C. $(x-10)^2+(y+6)^2=36$

The standard equation for a circle is $(x-a)^2+(y-b)^2=r^2$, where r is the radius and (a,b)= center of the circle such that a= abscissa and b= ordinate of center.

Given:- Center of circle=(10, –6) , radius r=6

Here abscissa of center a=10

ordinate of center b= -6

Substitute values of a, b and r in the standard equation of circle, we get

$(x-10)^2+(y-(-6))^2=6^2\\\Rightarrow(x-10)^2+(y+6)^2=36$

⇒ C is the correct answer.