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tamaranim1 [39]
3 years ago
7

Give a set of five integers, two positive and three negative, for which the mean, median, and mode are all -3

Mathematics
1 answer:
koban [17]3 years ago
7 0
That's 5 integers...

Logic tells me that a number divided by 5 should be equal to -3. -15/5 is in fact equal to -3.

Let's find 5 integers (two positive and three negative) when added up together equal -15.

-14, -3, -3, 2, 3.

[(-14)+(-3)+(-3)+2+3]/5 = (-15)/5 = -3

Mean = -3

----------

Now let's put these numbers in order, from lowest to highest - then pick out the middle value...

-14, -3, [-3], 2, 3

The median turns out to be -3.

------------

Let's look at the numbers once again...

-14, -3, -3, 2, 3

It turns out that -3 appears the most, therefore -3 is the mode too.
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Help!!!! Number 4 right answer
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The answer would be 0 solutions.

Here, we see <em>|</em><em />x+6<em>|</em><em /> = 2.
Oh wow! A foreign object!
|x+6|... two lines... what is that?

That is called absolute value. Whatever is inside the two lines, must have a positive answer!

Let's pretend we have a machine that has this absolute value function activated.
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Let's put in -6.

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So, for how many values <em>x</em> is |x+6|=-2 true?

None, because the answer <em>must</em><em /> be positive! 
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8 0
3 years ago
Find the value of x and y in the following figure where ABCD is a parallelogram<br><br>​
asambeis [7]

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5 0
3 years ago
(-4)(-4) use an exponent to rewrite the expression
DiKsa [7]
For this case we have the following expression:
<span> (-4)(-4) &#10;
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 an exponent to rewrite the expression is 2.</span>
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