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olganol [36]
3 years ago
14

Describe a method for writing an exponential equation given a graph

Mathematics
1 answer:
Dominik [7]3 years ago
3 0

Explanation:

We can find the parameters of the exponential equation ...

  y = a^(x-h) +k

1. Locate the horizontal asymptote. The y-value of that is the value of k.

2. Locate the point that is at y = k+1. The x-value of that is the value of h.

3. Locate the point that is at x = h+1. Subtract k from the y-value of that to find "a".

____

You have identified the three points on any exponential curve y = a^(x -h) +k. They are ...

  (-∞, k) for growth, or (∞, k) for decay

  (h, k+1)

  (h+1, k+a) . . . . . for decay, (h -1, k+1/a) might be easier to find

_____

<em>Comment on reflected curves</em>

If the curve extends below the horizontal asymptote, it has been reflected about the x-axis. Reflect it across the x-axis, perform the above steps, then multiply the right side of the equation by -1.

_____

<em>Additional note</em>

If the value of h is not an integer, it might be easier to express the curve in the form ...

   y = a·b^x +k

In this case, you can find the value of b by finding the y-values associated with three consecutive values of x. Call them (x, y1), (x+1, y2), (x+2, y3). Then ...

  b = (y3 -y2)/(y2 -y1)

  a = (y1 -k)/b^x . . . . . where x is the x-value of the first point, (x, y1)

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Answer:

18 J is the work required to stretch a spring from 7 m to 13 m.

Step-by-step explanation:

The work done is defined to be the product of the force F and the distance d  that the object moves:

W=Fd

If F is measured in newtons and d<em> </em>in meters, then the unit for is a newton-meter, which is called a joule (J).

This definition work as long as the force is constant, but if the force is variable like in this case, we have that the work done is given by

W=\int\limits^b_a {f(x)} \, dx

Hooke’s Law states that the force required to maintain a spring stretched x    units beyond its natural length is proportional to

f(x)=kx

where k is a positive constant (called the spring constant).

To find how much work W is required to stretch it from 7 m to 13 m you must:

Step 1: Find the spring constant

We know that the spring has a natural length of 7 m and a 4 N force is required to keep it stretched to a length of 11 m. So, applying Hooke’s Law

4=k(11-7)\\\\\frac{k\left(11-7\right)}{4}=\frac{4}{4}\\\\k=1

Thus F=x

Step 2: Find the the work done in stretching the spring from 7 m to 13 m.

Recall that the natural length is 7 m, so when we stretch the spring from 7 m to 13 m, we are stretching it by 6 m beyond its natural length.

Work needed to stretch it by 6 m beyond its natural length

W=\int\limits^6_0 {x} \, dx \\\\\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1\\\\\left[\frac{x^{1+1}}{1+1}\right]^6_0\\\\\left[\frac{x^2}{2}\right]^6_0=18

18 J is the work required to stretch a spring from 7 m to 13 m.

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Cal's score was a third of Able's score, so that means c = a/3. And since a = 6b, that means c = 6b / 3 = 2b.

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