Which statement is correct about the system of linear equations graphed below

Which equation represents a circle with the same center as the circle shown but with a radius of 2 units

Leona [35]

Answer:

Option B.

Step-by-step explanation:

Consider the below figure attached with this question.

From the below figure it is clear that the center of the given circle is (4,5).

The standard form of a circle is

$(x-h)^2+(y-k)^2=r^2$

where, (h,k) is center of the circle and r is radius.

We need to find the equation of a circle which represents the same center as the circle shown but with a radius of 2 units.

Substitute h=4, k=5 and r=2 in the above equation.

$(x-4)^2+(y-5)^2=(2)^2$

$(x-4)^2+(y-5)^2=4$

The required equation is $(x-4)^2+(y-5)^2=4$ .

Therefore, the correct option is B.

3 0

4 years ago

Read 2 more answers

The base of a triangular door wedge has an area of 55 square centimeters. The height of the wedge is 5 centimeters. Find the vol

V125BC [204]

Answer:

the answer ios yes

Step-by-step explanation:

55-243 equals the sum of 11

8 0

2 years ago

Ada is making fresh orange juice for her family. She discovers that for every 3 oranges she squeezes, she gets 5 ounces of juice

ycow [4]

The ratios that have the same constant of proportionality as Ada's observation 15/9, 30/18

According to the question:

We are required to select all the ratios that have the same constant of proportionality as Ada's observation.

let y and x represent amount of juice and oranges respectively;

y = juices squeezed out

x = Oranges squeezed in

y = k × x

5 = k × 3

5 = 3k

k = 5/3

The ratios equivalent to the constant of proportionality is 15/9, 30/18

Read more:

brainly.com/question/18611326

5 0

3 years ago

Listed below are the number of years it took for a random sample of college students to earn bachelor's degrees (based on data f

schepotkina [342]

Answer:

a) Mean = 6.5, sample standard deviation = 3.50

b) Standard error = 0.7826

c) Point estimate = 6.5

d) Confidence interval: (5.1469 ,7.8531)

Step-by-step explanation:

We are given the following data set for students to earn bachelor's degrees.

4, 4, 4, 4, 4, 4, 4.5, 4.5, 4.5, 4.5, 4.5, 4.5, 6, 6, 8, 9, 9, 13, 13, 15

a) Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{130}{20} = 6.5$

Sum of squares of differences = 6.25 + 6.25 + 6.25 + 6.25 + 6.25 + 6.25 + 4 + 4 + 4 + 4 + 4 + 4 + 0.25 + 0.25 + 2.25 + 6.25 + 6.25 + 42.25 + 42.25 + 72.25 = 233.5

$S.D = \sqrt{\frac{233.5}{19}} = 3.50$

b) Standard Error

$= \displaystyle\frac{s}{\sqrt{n}} = \frac{3.50}{\sqrt{20}} = 0.7826$

c) Point estimate for the mean time required for all college is given by the sample mean.

$\bar{x} = 6.5$

d) 90% Confidence interval:

$\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 19 and}~\alpha_{0.10} = \pm 1.729$

$6.5 \pm 1.729(\frac{3.50}{\sqrt{20}} ) = 6.5 \pm 1.3531 = (5.1469 ,7.8531)$

e) No, the confidence interval does not contain the value of 4 years. Thus, confidence interval is not a good estimator as most of the value in the sample is of 4 years. Most of the sample does not lie in the given confidence interval.

5 0

4 years ago

a vacuum is priced at$384 with allowed trade in of $140 on an old unit.If sales tax of 4 and 1 fourths % is charged on the price

Crank

Idk that's hard maybe 40

4 0

4 years ago