The answer is the same as the question. 1.75
Answer:
NO amount of hour passed between two consecutive times when the water in the tank is at its maximum height
Step-by-step explanation:
Given the water tank level modelled by the function h(t)=8cos(pi t /7)+11.5. At maximum height, the velocity of the water tank is zero
Velocity is the change in distance with respect to time.
V = {d(h(t)}/dt = -8π/7sin(πt/7)
At maximum height, -8π/7sin(πt/7) = 0
-Sin(πt/7) = 0
sin(πt/7) = 0
Taking the arcsin of both sides
arcsin(sin(πt/7)) = arcsin0
πt/7 = 0
t = 0
This shows that NO hour passed between two consecutive times when the water in the tank is at its maximum height
First, write out all the values:
40,41,41,45,48,48,49,49,49,50
Then to find the mean, you add all the values and divide by the number of values (there are 10 values)
(40+41+41+45+48+48+49+49+49+50)/10
460/10
=46
Hope this helps
34-0.5d=l
34-0.5d=26
34-26=0.5d
8=0.5d
8/0.5=d
16=d
16days
