y - 3
g(y) = ------------------
y^2 - 3y + 9
To find the c. v., we must differentiate this function g(y) and set the derivative equal to zero:
(y^2 - 3y + 9)(1) - (y - 3)(2y - 3)
g '(y) = --------------------------------------------
(y^2 - 3y + 9)^2
Note carefully: The denom. has no real roots, so division by zero is not going to be an issue here.
Simplifying the denominator of the derivative,
(y^2 - 3y + 9)(1) - (y - 3)(2y - 3) => y^2 - 3y + 9 - [2y^2 - 3y - 6y + 9], or
-y^2 + 6y
Setting this result = to 0 produces the equation y(-y + 6) = 0, so
y = 0 and y = 6. These are your critical values. You may or may not have max or min at one or the other.
Answer:
A. 2f + 10 = 28
Step-by-step explanation:
28 candy bars.
He wants 10.
28 - 10.
18 candy bars.
He gives each friend 2.
18 divided by 2.
9.
He can treat 9 friends.
Step 1: Subtract 10 from both sides.
2f+10=28
which would take away the 10 and subtract 10 from 28. (That would be Jack's bars.)
2f = 28.
Step 2: Divide by 2 on both sides.
2f = 28
which would cancel out the 2f. And Whatever is done to the left is done to the right, meaning you would divide 28 by 2 aswell. (Dividing up the candy bars among his friends).
f = 9
Answer:
Step-by-step explanation:
One of the rules of logarithms is ...
log(a^b) = b·log(a)
So ...
For this case we must algebraically rewrite the given expression. So:
x: It is the variable that represents an unknown number
"double a number" is represented as: 
"6 less than double a number" is represented as: 
So, the final expression is:
If we want to rewrite the expression in an equivalent way, we take common factor 2:
Asnwer:
Equivalent expression:
Answer: 53
Step-by-step explanation: It is the only prime
