Step-by-step explanation:
Let the original speed of the train be x km/h.
Time taken to cover a distance of 360 km = 360/x hours.
New speed of the train = (x+5) km/h.
Time taken to cover a distance of 360 km at new speed = 360/x+5 hours.
Since, the train takes 1 hour less time,
∴360/x - 360/ x+5 = 1
⇒360 (5) = x² + 5x
⇒1800 = x² + 5x
⇒x² + 5x - 1800 = 0
⇒x² + 45x - 40x - 1800 = 0
⇒x (x+45) - 40( x +45) = 0
⇒(x+45) (x-40) = 0
⇒x = (-45), 40
But since speed cannot be in negative.
∴x = 40 km/hr.
Hence, the original speed of the train is 40 km/h.
So step one is to distribute the 4x through and the -5 through. After distributing you get 8x^{2}+28x-15x+10. Combine the like terms, 28x and -15x, to get 13x. Your answer is 8x^{2}+13x+10
A different way to do this is doing adding
1.) 3/4 + 3/4 + 3/4 + 3/4 = 12/4 = 3
Another way is reducing
12/4 = 3
I hope this helps
if this does not include a number answer, it could be
(1 × X) - 4
Answer:
(3, - 1 )
Step-by-step explanation:
Given the 2 equations
x - 3y = 6 → (1)
2x + 2y = 4 → (2)
Rearrange (1) expressing x in terms of y by adding 3y to both sides
x = 6 + 3y → (3)
Substitute x = 6 + 3y into (2)
2(6 + 3y) + 2y = 4 ← distribute and simplify left side
12 + 6y + 2y = 4
12 + 8y = 4 ( subtract 12 from both sides )
8y = - 8 ( divide both sides by 8 )
y = - 1
Substitute y = - 1 into (3) for corresponding value of x
x = 6 + 3(- 1) = 6 - 3 = 3
Solution is (3, - 1 )