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igor_vitrenko [27]
3 years ago
6

Please HELP me lol I need it !!

Mathematics
1 answer:
Xelga [282]3 years ago
6 0
Graph D.
The interval goes from -1 to 4. -1 is included so it'll have a filled circle. 4 isn't included so it'll have a hollow circle.
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The area of one of the smaller circles is 8/ in². Find the area of the shaded region.
Ksju [112]

Answer:

Area of shaded region = 16π in² (D)

Step-by-step explanation:

The question is incomplete without the diagram if the circles. Find attached the diagram used in solving the question.

Area of the smaller circle = 8π in²

Area of a circle = πr²

πr² = 8π

r² =8

r = √8 = 2√2

From the diagram, there are two smaller circles in a bigger circle.

The radius of the bigger circle (R) is 2times the radius of the smaller circle (r)

R = 2r

Area of bigger circle = πR²

= π×(2r)² =   π×(2×2√2)²

= π×(4√2)² = π×16×(√2)²

Area of bigger circle = π×16×2

Area of bigger circle = 32π in²

Since there are two smaller circles in a bigger circle

Area of shaded region = Area of bigger circle -2(area of smaller circles)

Area of shaded region = 32π in² - 2(8π in²)

Area of shaded region = 32π in² - 16π in²

Area of shaded region = 16π in²

8 0
3 years ago
0.482 × 61.2² ÷√98.01
mixer [17]

Answer:

Use by Prime factorisation method

3 0
2 years ago
What is eight g plus ten equals thirty five plus three g
gtnhenbr [62]

8g+10=35+3g You need to find what number g is, just plug in random numbers till both sides are equal

8 0
3 years ago
Offering 40 points and brainliest for answer
Nata [24]
In fact, this problem belongs to the chemistry section.  Recall that many other sciences require mathematical calculations.  The problem will belong to Mathematics only if no knowledge of other sciences are required to solve the problem.

Solubility for the given substances is measured in grams per 100 g of water at a particular temperature (20 deg.C).
This means that the mass (assumed to be the solute) will not change the solubility, just the minimum quantity of solvent (water) will.
Thus the solubility of sodium chloride will remain L=36 g/100g H2O for any quantity of solute.  Similarly, the solubility of lead nitrate will remain as K=54 g/100 g H2O.

The reason that they remain constant is because the quantity of solvent (water) is fixed at 100 g.  Varying amount of solute will affect the quantity of solvent required, but not the solubility.
I'll leave it to you to calculate the difference between K & L.
8 0
3 years ago
write an equation in slope intercept form of the line with a slope- 2 and y intercept 3. Graph the line
charle [14.2K]

Answer:

y = -2x + 3

Step-by-step explanation:

<u>Step 1:  Find out what each part of slope intercept form is</u>

Slope Intercept Form:  y = mx + b

<em>m is the slope</em>

<em>b is the y-intercept</em>

<u>Step 2:  Plug in the information into the formula</u>

m/slope = -2

b/y-int = 3

<em>y = -2x + 3</em>

<em />

Answer:  y = -2x + 3

4 0
3 years ago
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