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navik [9.2K]
2 years ago
11

WILL GIVE BRAINLIEST

Mathematics
1 answer:
patriot [66]2 years ago
8 0
The answer would be the first one or the second one but I think it’s the x over 3
You might be interested in
<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%2072" id="TexFormula1" title="\sqrt{x} 72" alt="\sqrt{x} 72" align="absmiddle"
AveGali [126]

Answer:

Step-by-step explanation:

√x^72 = √(x^36)^2 = x^36

4 0
3 years ago
A cellular phone company monitors monthly phone usage. The following data represent the monthly phone use in minutes of one part
Sergeu [11.5K]

Answer:

The standard deviation increased but there was no change in the interquantile range          

Step-by-step explanation:

We are given the following data in the question:

320, 411, 348, 537, 420, 449, 462, 403, 454, 517, 515, 358, 438, 541, 387, 368, 502, 437, 431, 428.

n = 20

a) Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{8726}{20} = 436.3

Sum of squares of differences =

13525.69 + 640.09 + 7796.89 + 10140.49 + 265.69 + 161.29 + 660.49 + 1108.89 + 313.29 + 6512.49 + 6193.69 + 6130.89 + 2.89 + 10962.09 + 2430.49 + 4664.89 + 4316.49 + 0.49 + 28.09 + 68.89 = 75924.2

S.D = \sqrt{\frac{75924.2}{19}} = 63.21

Sorted Data = 320, 348, 358, 368, 387, 403, 411, 420, 428, 431, 437, 438, 449, 454, 462, 502, 515, 517, 537, 541

IQR = Q_3 - Q_1\\Q_3 = \text{upper median},\\Q_1 = \text{ lower median}

Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}

Median = \frac{431 + 437}{2} = 434

Q_1 = \frac{387 + 403}{2} = 395\\\\Q_3 = \frac{462 + 502}{2} = 482

IQR = 482 - 395 = 87

b) After changing the observation

0, 411, 348, 537, 420, 449, 462, 403, 454, 517, 515, 358, 438, 541, 387, 368, 502, 437, 431, 428

Mean =\displaystyle\frac{8406}{20} = 420.3

Sum of squares of differences =

176652.09 + 86.49 + 5227.29 + 13618.89 + 0.09 + 823.69 + 1738.89 + 299.29 + 1135.69 + 9350.89 + 8968.09 + 3881.29 + 313.29 + 14568.49 + 1108.89 + 2735.29 + 6674.89 + 278.89 + 114.49 + 59.29 = 247636.2

S.D = \sqrt{\frac{247636.2}{19}} = 114.16

Sorted Data = 0, 348, 358, 368, 387, 403, 411, 420, 428, 431, 437, 438, 449, 454, 462, 502, 515, 517, 537, 541

Median = \frac{431 + 437}{2} = 434

Q_1 = \frac{387 + 403}{2} = 395\\\\Q_3 = \frac{462 + 502}{2} = 482

IQR = 482 - 395 = 87

Thus. the standard deviation increased but there was no change in the interquantile range.

5 0
3 years ago
Explain why x^2 + y^2 -6x +10y = -34 is NOT a circle. What is it?
kenny6666 [7]

Answer:

(See explanation for further details)

Step-by-step explanation:

The expression is transformed into its standard form:

x^{2} + y^{2} - 6\cdot x + 10\cdot y + 34 = 0

x^{2} - 6\cdot x + 9 + y^{2} + 10\cdot y + 25 = 0

(x-3)^{2} + (y+5)^{2} = 0

The function does not represent a circle, as radius is a positive number.

4 0
3 years ago
Let P2 denote the vector space of all polynomials with degree less than or equal to 2. (a) Show that B = {1 + x + x 2 , 1 + 2x −
nirvana33 [79]

Answer:

The answer is in the the attachment

Step-by-step explanation:

The question you posted was incomplete but i believe below is the complete question;

Let P2 denote the vector space of all polynomials with degree less than or equal to 2. (

a) Show that B = {1 + x + x 2 , 1 + 2x − x 2 , 1 − 2x − x 2} is a basis for P2.

(b) Find the coordinate vector of p(x) = 1 + 2x + 3x 2 relative to the basis B

The answer is explained in the attachments.

7 0
3 years ago
8 3/ 4 as a decimal.
dem82 [27]
Your answer is 8.25 hope this help also remember to hit that brainliest button

4 0
3 years ago
Read 2 more answers
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