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3 years ago

How do you use the digits in a hundredths decimal to write a percent?

Mathematics

1 answer:

bixtya [17]3 years ago

5 0

Explanation:

"Percent" literally means "per hundred" or "divided by 100". The percent symbol (%) is a shorthand way to write /100 ("divided by 100," or "hundredths"). So, hundredths and percent are essentially the same thing.

Given a "hundredths decimal", move the decimal point 2 places to the right and add a % symbol. (Moving the decimal point multiplies the number by 100; adding the % symbol divides it by 100, so the end result is the same value written in a different form.)

Example:

19% = 19/100 = 0.19 . . . . (nineteen percent = nineteen hundredths)

and in the other direction, ...

0.53 = 53/100 = 53% . . . . (fifty-three hundredths = fifty-three percent)

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In a football tournament, the Bees scored 9 less than three times as many points as the Hornets. The Wasps scored 28 more points

gladu [14]

B = bees, w = wasps, x = hornets

b + w + x = 184
b = 3x - 9
w = x + 28

(3x - 9) + (x + 28) + x = 184...combine like terms
5x + 19 = 184
5x = 184 - 19
5x = 165
x = 165/5
x = 33 <== points scored by Hornets

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goldfiish [28.3K]

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Step-by-step explanation:

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Tammy received a $70 gift card for a coffee store. She used it in buying some coffee that cost $8.41 per pound. After buying the

Ivahew [28]

Total money Tammy has = $70

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Therefore, the money she used on coffee =

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1 pound coffee costs $8.41

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3 years ago

Find the value of the expression. 7! ÷ 3! 5,040 5,034 840 24

koban [17]

First, let's review what the "factorial operator" ! means.

5! = 5*4*3*2*1.

3! = 3*2*1

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3 years ago

Find all possible values of α+

const2013 [10]

Answer:

$\rm\displaystyle 0,\pm\pi$

Step-by-step explanation:

please note that to find but α+β+γ in other words the sum of α,β and γ not α,β and γ individually so it's not an equation

===========================

we want to find all possible values of α+β+γ when tanα+tanβ+tanγ = tanαtanβtanγ to do so we can use algebra and trigonometric skills first

cancel tanγ from both sides which yields:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \alpha ) \tan( \beta ) \tan( \gamma ) - \tan( \gamma )$

factor out tanγ:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \gamma ) (\tan( \alpha ) \tan( \beta ) - 1)$

divide both sides by tanαtanβ-1 and that yields:

$\rm\displaystyle \tan( \gamma ) = \frac{ \tan( \alpha ) + \tan( \beta ) }{ \tan( \alpha ) \tan( \beta ) - 1}$

multiply both numerator and denominator by-1 which yields:

$\rm\displaystyle \tan( \gamma ) = - \bigg(\frac{ \tan( \alpha ) + \tan( \beta ) }{ 1 - \tan( \alpha ) \tan( \beta ) } \bigg)$

recall angle sum indentity of tan:

$\rm\displaystyle \tan( \gamma ) = - \tan( \alpha + \beta )$

let α+β be t and transform:

$\rm\displaystyle \tan( \gamma ) = - \tan( t)$

remember that tan(t)=tan(t±kπ) so

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm k\pi )$

therefore when k is 1 we obtain:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm \pi )$

remember Opposite Angle identity of tan function i.e -tan(x)=tan(-x) thus

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm \pi )$

recall that if we have common trigonometric function in both sides then the angle must equal which yields:

$\rm\displaystyle \gamma = - \alpha - \beta \pm \pi$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ \pm \pi }$

when is 0:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta \pm 0 )$

likewise by Opposite Angle Identity we obtain:

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm 0 )$

recall that if we have common trigonometric function in both sides then the angle must equal therefore:

$\rm\displaystyle \gamma = - \alpha - \beta \pm 0$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ 0 }$

and we're done!

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