Question

Needing some help please!!

Answer 1

Answer:

a. 2

b. 3

c. 3x^2+9x+15

d. 257

Step-by-step explanation:

$f(x)=x^{2}+1 \\g(x)=3x+4$

When a function is written like that the value in the parenthesis is what you use to replace the x inside the expression.

a. f(-1) means the value of function "f" when x = -1

$f(-1)=(-1)^{2}+1=1+1=2$

b. "f" when x = -2 + "g" when x = -2

$f(-2)+g(-2)=(-2)^{2}+1+3(-2)+4=3$

c. multiply for 3 each function

$3f(x)+3g(x)=3(x^{2}+1)+3(3x+4)=3x^{2}+9x+15$

d. "g" when x = 4 then "f" when x = g(4)

$g(4)=3(4)+4= 16\\f(g(4))=f(16)=16^{2}+1 = 257$