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Shalnov [3]
4 years ago
9

Team:Round to the nearest whole: 90.1​

Mathematics
2 answers:
Katen [24]4 years ago
8 0

Answer:

Step-by-step explanation:

90

geniusboy [140]4 years ago
5 0

Answer:

The nearest whole would be 90

Step-by-step explanation:

If you are rounding a number, 1 -4 makes the number go down, for example 1.4 would round to 1. 5-9 would round up, for example, 1.8 would round to 2

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posledela

Using the <em>normal distribution and the central limit theorem</em>, it is found that the power of the test is of 0.9992 = 99.92%.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem:

  • The mean is \mu = 8.5.
  • The standard deviation is \sigma = 0.87.
  • A sample of 30 is taken, hence n = 30, s = \frac{0.87}{\sqrt{30}} = 0.1588.

The power of the test is given by the probability of a sample mean above 8, which is <u>1 subtracted by the p-value of Z when X = 8</u>, so:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem:

Z = \frac{X - \mu}{s}

Z = \frac{8 - 8.5}{0.1588}

Z = -3.15

Z = -3.15 has a p-value of 0.0008.

1 - 0.0008 = 0.9992.

The power of the test is of 0.9992 = 99.92%.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can check brainly.com/question/24663213

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