All categories

2 years ago

If each of the cubes in a Rubik's Cube represented 1 cubic inch, what would be the volume of the Rubik's Cube?

Mathematics

1 answer:

kicyunya [14]2 years ago

5 0

Answer:

The volume of the Rubik's Cube is 27 in^3

Step-by-step explanation:

Each face of a Rubik's Cube has 3x3 cubes, then each face has 9 small cubes.

We can think of a Rubik's Cube as 3 pieces, such that each piece has 9 small cubes on it, and the 3 pieces are: Front side, middle part, back part.

Then the total number of small cubes on a Rubik's cube is 9*3 = 27 small cubes.

Now we know that each one of these small cubes has a volume of 1 in^3

Then the volume of 27 of these cubes is 27 times the volume of a single smaller cube, then the volume of the Rubik's Cube is:

V = 27*( 1 in^3) = 27 in^3

You might be interested in

ANSWER THIS PLS!!!!

astra-53 [7]

Answer and Step-by-step explanation: With the constant velocity motion formula, we can determine constant velocity of the object in motion whose data we collected:

x = x₀ + vt

Velocity can be calculated as:

$v=\frac{x-x_{0}}{t}$

$v=\frac{70-40}{10}$

v = 3 m/s

The beginning of the data collect, object is 40m away, then x₀ = 40.

So, equation modeling the object's path is x = 40 + 3t.

5 0

3 years ago

9.84 x 0.26 SHOW WORK!!!!!!!!!!!!!!!

Andrews [41]

Answer:

2.5584

Step-by-step explanation:

9.84 * 0.26

= 9.84(0.2 + 0.06)

= 1.968 + 0.5904

= 2.5584

8 0

2 years ago

Read 2 more answers

Suppose lines EF and GH are reflected over the line Y equals X to form the lines JK and LM which statement would be true about t

katrin [286]

Answer:

A) JK and LM will be parallel to each other.

Step-by-step explanation:

On reflection on $y=x$ line the x co-ordinate changes with y co-ordinate and y co-ordinate changes with x co-ordinate

$(x,y)\rightarrow (y,x)$

Points on line EF

$(0,6) , (-5,-2)$

On reflection of this line on $y=x$ the new points we get for line JK are

$(6,0),(-2,-5)$

Points on line GH

$(-4,9),(-9,1)$

On reflection on y=x line the new points we get for line LM are

$(9,-4),(1,-9)$

Slope of line JK

$m=\frac{y_2-y_1}{x2-x1}\\m=\frac{(-5)-0}{(-2)-6} \\m=\frac{-5}{-8}=\frac{5}{8}$

Slope of line LM

$m=\frac{y_2-y_1}{x2-x1}\\m=\frac{(-9)-(-4)}{1-9} \\m=\frac{-9+4}{-8}=\frac{-5}{-8}\\m=\frac{5}{8}$

For two line to be parallel, their slopes will be same.

$m_{JK} =\frac{5}{8} , m_{LM}=\frac{5}{8}$

Since slopes of lines JK and LM are same therefore we can say that these are parallel to each other.

5 0

3 years ago

Find the ninth term of the sequence sqrt 5, sqrt 10, ^2sqrt 5

hjlf

The rule of geometric sequence is ⇒⇒⇒ a * r^(n-1)
Where a is the first term and r is the common ratio
for the given sequence √5 , √10 , 2√5 , .......
a = √5
r = √10 / √5 = √2
The ninth term = √5 * (√2)^(9-1) = √5 * (√2)⁸ = 16 √5

the correct answer is the third option 16√5

5 0

3 years ago

How do I get the answer for exponents? Please explain step by step to get marked!

ioda

Answer:

4900

Step-by-step explanation:

70^2 means 70*70

70*70=4900

3 0

2 years ago

Read 2 more answers