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Ksenya-84 [330]
3 years ago
7

Need help What is the value of x??

Mathematics
1 answer:
Luden [163]3 years ago
3 0
Hey there...
The answer to ur question is option(C.)=>120
Since AB parallel CD
=>alternate interior angles are equal....
You might be interested in
Simplify:<br> -4x^2(3x-7)
statuscvo [17]
The answer is:  " -12x³ + 28x² "  .
___________________________________________
Explanation:
___________________________________________
Note the "distributive property of multiplication" :
___________________________________________a(b+c) =  ab +  ac ;a(b−c) =  ab − ac ;___________________________________________
So;  given:  " - 4x² (3x - 7) " ;

 →   - 4x² (3x <span>−</span> 7) ;
             = [ -4x² * 3x ]  −  [- 4x² * -7 ]  ;
 
             =  -12x³ − (28x²) ;

             =  -12x³ − 28x²  .
_______________________________________________________
8 0
3 years ago
Please my last question I need help<br> Please
nevsk [136]

Answer:

to graph this, you will need to plot points on the graph

the x-axis as stated in the instructions will be the distance in miles

the y-axis will be the time in minutes

for every 1 mile Gloria bikes, it takes her 5 minutes

so that gives us our first point on the graph (1,5)

what about 2 miles? we would double the amount of minutes spent and that would take Gloria 10 minutes to bike 2 miles

that is another point on our graph (2,10)

same goes for the rest of the points, 3 miles would be equal to 15 minutes etc.

I have attached a graph that should be similar to what you can come up with, I put the y-axis (minutes) in intervals of 5, and the x-axis from 1-5

3 0
4 years ago
Pls help with the question below
harina [27]
The answer is m = 7/5 (decimal form is 1.4)




6 0
2 years ago
Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE
EleoNora [17]

Answer:

0, 10

Step-by-step explanation:

The given function is:

g(y) = \frac{y-5}{y^2-3y+15}

According to the quotient rule:

d(\frac{f(y)}{h(y)})  = \frac{f(y)*h'(y)-h(y)*f'(y)}{h^2(y)}

Applying the quotient rule:

g(y) = \frac{y-5}{y^2-3y+15}\\g'(y)=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}

The values for which g'(y) are zero are the critical points:

g'(y)=0=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}\\(y-5)*(2y-3)-(y^2-3y+15)=0\\2y^2-3y-10y+15-y^2+3y-15\\y^2-10y=0\\y=\frac{10\pm \sqrt 100}{2}\\y_1=\frac{10-10}{2}= 0\\y_2=\frac{10+10}{2}=10

The critical values are y = 0 and y = 10.

5 0
3 years ago
Which of these is a geometric sequence?
gizmo_the_mogwai [7]
A geometric sequence deals with multiplying...u have to multiply by a common number to get the next number

1/4 * 2 = 1/2
1/2 * 2 = 1
1 * 2 = 2
2 * 2 = 4

so ur geometric sequence is : 1/4, 1/2, 1, 2, 4...with a common ratio of 2
8 0
3 years ago
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