<span>
A)
C(102) = 102^2 – 400 = 10004
</span>C(100) = 100^2 – 400 = 9600
average rate of change = (10004<span>- 9600)/(102 - 100) = 404/2 = 202
</span>B)
C' = 2x = 2 (100) = 200
Answer:
Step-by-step explanation:
- This is a neat question. I suggest that you graph it on desmos. You will lean a bunch by doing it. These are the graphs you should put on there.
- y = 1/(abs(x - a) - 1):In red
- When you use your down arrow, a new entry will be given you. You can use your mouse to operate the slider you get when you type a = 5
- so your next graph should be a = 5
- Use your down arrow again. Put in x = 4: Blue Line
- Use your down arrow again. Put in x = 6: Green Line
Be patient with this. Play with the sliders to see what they do. I believe you are correct, but I am not certain of the second union although it does look correct.
The graph I have enclosed is of what I have described in the steps above. Make sure you try it all out.
Answer:
Let x be the number of silver medals.
As there were two more gold medals than silver ones, gold medals are x+2
We also know that the number of bronze medals was 4 less than the sum of gold and silver, so if there are x + 2 of gold and x of silver, there are x+x+2-4 of bronze.
Now, we can do an equation, as we know there were a total of 28 medals:
x + x + 2 + x + x + 2 - 4 = 28
And we isolate x:
4x = 28
x = 28/4 = 7
There were 7 silver medals, so there were 9 gold ones (7-2) and 12 of bronze (9+7-4).
Answer:
the not simplified answer is 6/28 The GCF is 2 the siplified answer is 3/14
Step-by-step explanation: