Answer:
Step-by-step explanation:
radius=diameter/2
=8/2
=4 m
volume of a cylinder =πr^2h
=3.14*(4)^2*13
=40.82*16
=653.12 m^3
Answer:
x<9
Step-by-step explanation:
Answer:
14
Step-by-step explanation:
p=$1000
rate percent=1.4%
time=one year
then
1.4/100*100=14
![\\ \text{Michael distrinutes 2345 packages of screws into 5 equal groups for shipping.}\\ \\ \text{we need to find the number of packages of screws in each group.}\\ \\ \text{so for this we use the unitary method.}\\ \\ \text{The number of packages of screws in 5 groups}=2345\\ \\ \text{so the number of packages of screws in 1 group}=\frac{2345}{5}\\ \\ =469](https://tex.z-dn.net/?f=%5C%5C%0A%5Ctext%7BMichael%20distrinutes%20%202345%20packages%20of%20screws%20into%205%20equal%20groups%20for%20shipping.%7D%5C%5C%0A%5C%5C%0A%5Ctext%7Bwe%20need%20to%20find%20the%20number%20of%20packages%20of%20screws%20in%20each%20group.%7D%5C%5C%0A%5C%5C%0A%5Ctext%7Bso%20for%20this%20we%20use%20the%20unitary%20method.%7D%5C%5C%0A%5C%5C%0A%5Ctext%7BThe%20number%20of%20packages%20of%20screws%20in%205%20groups%7D%3D2345%5C%5C%0A%5C%5C%0A%5Ctext%7Bso%20the%20number%20of%20packages%20of%20screws%20in%201%20group%7D%3D%5Cfrac%7B2345%7D%7B5%7D%5C%5C%0A%5C%5C%0A%3D469)
Hence the number of packages of screws in each shipping box is: 469
Hence option (B) is correct.
7.
(2b^2+7b^2+b)+(2b^2-4b-12)
(9b^2+b)+(2b^2-4b-12)
9b^2+b+2b^2-4b-12
11b^2+b-4b-12
11b^2-3b-12
8.
(7g^3+4g-1)+(2g^2-6g+2)
7g^3+4g-1+2g^2-6g+2
7g^3-2g-1+2g^2+2
7g^3-2g+1+2g^2
7g^3+2g^2-2g+1
Hope this helps!