A cube has sides that are all equal lengths .
Volume of a cube is S^3, where S is the length of the side.
Volume = 3^3 = 3 x 3 x 3 = 27 cubic inches.
The area of sector is 1.57 m²
<u>Explanation:</u>
Given:
Radius, r = 3 m
Central angle of a sector = 1/9π radians
Area of sector, A = ?
We know:
Area of sector, A = 
where,
α is the central angle in radians
On substituting the value we get:

Therefore, the area of sector is 1.57 m²
Using the binomial distribution, it is found that there is a 0.0328 = 3.28% probability that at least 2 of them choose the same quote.
<h3>What is the binomial distribution formula?</h3>
The formula is:


The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem, we have that:
- There are 6 students, hence n = 6.
- There are 20 quotes, hence the probability of each being chosen is p = 1/20 = 0.05.
The probability of one quote being chosen at least two times is given by:

In which:
P(X < 2) = P(X = 0) + P(X = 1).
Then:



Then:
P(X < 2) = P(X = 0) + P(X = 1) = 0.7351 + 0.2321 = 0.9672.

0.0328 = 3.28% probability that at least 2 of them choose the same quote.
More can be learned about the binomial distribution at brainly.com/question/24863377
Answer:
B) 8 ≤ p
Step-by-step explanation:
1000 - 380 = 620
620 / 80 = 7.75
Round it up to 8