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2 years ago

Solve for x 5x+5x+3=4(2x+1)-2

1 answer:

6 0

We need to add like terms and distribute before we try to isolate X.
10x+3=8x+4-2
10x+3=8x+2

Now let's isolate x. We should start with subtracting 8x from both sides.
2x+3=2
Now, let's subtract 3 from both sides.
2x=-1
Now divide each side by 2.
X=-0.5
We now know x is -0.5, so let's check.
5(-0.5)+5(-0.5)+3=4[2(-0.5)+1]-2
-2.5-2.5+3=4(0)-2
-5+3=0-2
-2=-2

So, X= -0.5

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Professor wonders whether a student's homework average (X) could be used to predict their final grade in the course (Y) . She ca

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The dependent variable is the final grade in the course and is the vriable of interest on this case.

H0: $\beta_1 = 0$

H1: $\beta_1 \neq 0$

And if we reject the null hypothesis we can conclude that we have a significant relationship between the two variables analyzed.

Step-by-step explanation:

On this case w ehave the following linear model:

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Which is the dependent variable, and why?

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Based on the material taught in this course, which of the following is the most appropriate alternative hypothesis to use for resolving this question?

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H0: $\beta_1 = 0$

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2 years ago

What is each power of i with its multiplicative inverse.

pentagon [3]

Answer:

1) multiplicative inverse of i = -i

2) Multiplicative inverse of i^2 = -1

3) Multiplicative inverse of i^3 = i

4) Multiplicative inverse of i^4 = 1

Step-by-step explanation:

We have to find multiplicative inverse of each of the following.

1) i

The multiplicative inverse is 1/i

if i is in the denominator we find their conjugate

$=1/i * i/i\\=i/i^2\\=We\,\, know\,\, that\,\, i^2 = -1\\=i/(-1)\\= -i$

So, multiplicative inverse of i = -i

2) i^2

The multiplicative inverse is 1/i^2

We know that i^2 = -1

1/-1 = -1

so, Multiplicative inverse of i^2 = -1

3) i^3

The multiplicative inverse is 1/i^3

We know that i^2 = -1

and i^3 = i.i^2

$1/i^3\\=1/i.i^2 \\=1/i(-1)\\=-1/i * i/i\\=-i/i^2\\= -i/-1\\= i$

so, Multiplicative inverse of i^3 = i

4) i^4

The multiplicative inverse is 1/i^4

We know that i^2 = -1

and i^4 = i^2.i^2

$=1/i^2.i^2\\=1/(-1)(-1)\\=1/1\\=1$

so, Multiplicative inverse of i^4 = 1

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2 years ago

Evaluate 5x – 2y + (7x – y) for x = 7 and y = –2

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Answer:

Step-by-step explanation:

5x – 2y + (7x – y)

Combine like terms

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Let x = 7 and y = -2

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