Answer:
so the answer will be 1
Step-by-step explanation:
An oil tanker can be emptied by the main pump in 5 hours.
An auxilary pump can empty the tanker in 14 hours.
If the main pump is started at 7pm, when should the auxilary pump be started
so that the tanker is emptied by 11pm?
:
Let t = no. of hrs to run the Aux pump
:
The main pump will run 4 hr (7 - 11 pm)
:
Let the completed job = 1; (an empty Tanker)
:
The shared work equation
4%2F5 + t%2F14 = 1
Multiply equation by 70 to get rid of the equation, results:
14(4) + 5t = 70
56 + 5t = 70
5t = 70 - 56
5t = 14
t = 14%2F5
t = 2.8 hrs to run the aux pump
:
2.8 hr = 2 + .8(60) = 2 hrs 48 min
:
Subtract 2:48 from 11:00 = 8:12 PM start the aux pump
;
;
Check solution
4/5 + 2.8/14 =
.8 + .2 = 1
P would equal negative three.
A number that can add up to 10 and multiplies to 11 is 1 since 11 is a prime number
3+1/x *x = 7/x*x
3x+1 = 7
3x+1-1=7-1
3x=6
3x/3 =6/3
x =2
Average must be 225 or more
4 games so
score1=192
score2=214
score3=250
score4=?
so
times both sides by 4 to clear fraction
656+?≥900
minus 656 from both sides
?≥244
min score is 244
