I need the picture in order to see what angle x is :)
D because I answered it at school and it was correct
Answer:
In a certain Algebra 2 class of 30 students, 22 of them play basketball and 18 of them play baseball. There are 3 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
I know how to calculate the probability of students play both basketball and baseball which is 1330 because 22+18+3=43 and 43−30 will give you the number of students plays both sports.
But how would you find the probability using the formula P(A∩B)=P(A)×p(B)?
Thank you for all of the help.
That formula only works if events A (play basketball) and B (play baseball) are independent, but they are not in this case, since out of the 18 players that play baseball, 13 play basketball, and hence P(A|B)=1318<2230=P(A) (in other words: one who plays basketball is less likely to play basketball as well in comparison to someone who does not play baseball, i.e. playing baseball and playing basketball are negatively (or inversely) correlated)
So: the two events are not independent, and so that formula doesn't work.
Fortunately, a formula that does work (always!) is:
P(A∪B)=P(A)+P(B)−P(A∩B)
Hence:
P(A∩B)=P(A)+P(B)−P(A∪B)=2230+1830−2730=1330
The equivalent expression of 
is 
<h3>How to determine the equivalent expression?</h3>
The expression is given as:
Expand the numerator
Divide 125 and 30 by 5
Apply the law of indices
Evaluate the exponent
Hence, the equivalent expression of is
Read more about equivalent expression at:
brainly.com/question/2972832
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Answer:
Step-by-step explanation:
Give the fractions a common denominator
11/13 + 4/7 = 77/91 + 52/91
= 129/91
