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natima [27]
3 years ago
7

Alicia bought a notebook and several erasers at the student store. The graph shows the relationship between the total cost of he

r items and the number of erasers she purchased.
What is the cost of each eraser?

a
$1.00
b
$2.00
c
$1.50
d
$3.50

Mathematics
2 answers:
melomori [17]3 years ago
6 0
<h3><u>Answer:</u></h3>

Option: C is the correct answer.

$ 1.50 is the cost of 1 eraser.

<h3><u>Step-by-step explanation:</u></h3>

Alicia bought a notebook and several erasers at the student store.

Let the cost of 1 eraser=$ x.

Now from the scatter plot we could see that when Alicia did not bought any eraser then her total cost =$ 2.

That means cost of a notebook=$ 2.

Now when she buys a notebook and two eraser then she pays=$ 5.

i.e.

Total cost=cost of notebook+ 2× cost of 1 eraser

Total cost=cost of notebook+2×x

i.e.

5=2+2x

⇒ 2x=5-2

⇒ 2x=3

⇒ x=1.5

Hence, cost of one eraser is:

$ 1.50

bija089 [108]3 years ago
4 0

Answer:

(B) $1.50

Step-by-step explanation:

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Answer:

c = 10 feet

Step-by-step explanation:

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<u>Step 1:  Plug in the information</u>

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7 0
3 years ago
Given the domain (-2,2,4) what is the range for the relation 3x-y=3
Bumek [7]

Answer:

Given the domain, the range for 3x-y = 3 is {-9, 6, 9}

Step-by-step explanation:

First you have to put the relation in terms of y ⇒ 3x - y = 3⇒ 3x -3 = y

⇒ y = 3x - 3.

Then you replace the values indicated by the domain to find their "y" values (the ones that constitute the range).

f(-2) = -9

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Finally, the range for the given domain is {-9, 6, 9}

3 0
3 years ago
Carlos is using the quadratic formula to find the solutions of y=3x^2-5x-2. Which of the following will simplify to the correct
Nana76 [90]

Answer:

Fx=\frac{5\pm\sqrt{25+24} }{6}

Step-by-step explanation:

A quadratic equation in one variable given by the general expression:

ax^2+bx+c

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The roots of this equation can be found using the quadratic formula, which is given by:

x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}

So:

y(x)=3x^2-5x-2=0

As you can see, in this case:

a=3\\b=-5\\c=-2

Using the quadratic formula:

x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}=\frac{-(-5)\pm\sqrt{(-5)^2-4(3)(-2)} }{2(3)}=\frac{5\pm\sqrt{25+24} }{6}

Therefore, the answer is:

Fx=\frac{5\pm\sqrt{25+24} }{6}

4 0
3 years ago
Help! If you know this can you tell me how to do it?
aleksandr82 [10.1K]

Answer:

c

Step-by-step explanation:

Here's how this works:

Get everything together into one fraction by finding the LCD and doing the math.  The LCD is sin(x) cos(x).  Multiplying that in to each term looks like this:

[sin(x)cos(x)]\frac{sin(x)}{cos(x)}+[sin(x)cos(x)]\frac{cos(x)}{sin(x)} =?

In the first term, the cos(x)'s cancel out, and in the second term the sin(x)'s cancel out, leaving:

\frac{sin^2(x)}{sin(x)cos(x)}+\frac{cos^2(x)}{sin(x)cos(x)}=?

Put everything over the common denominator now:

\frac{sin^2(x)+cos^2(x)}{sin(x)cos(x)}=?

Since sin^2(x)+cos^2(x)=1, we will make that substitution:

\frac{1}{sin(x)cos(x)}

We could separate that fraction into 2:

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Therefore, the simplification is

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5 0
3 years ago
Which diagram represents the postulate that states exactly one line exists between any two points?
likoan [24]

Answer:

Check attachment for the diagram

Step-by-step explanation:

Given two points A and B in the diagram attached, we see that exactly one line exists between these points.

6 0
3 years ago
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