Question

If a coin is thrown with a starting velocity of 0 m/s down a dry well and hits bottom in 1.2 s, what's the depth of the well?

Answer 1

Answer:

$H=7.0632m$

Step-by-step explanation:

Since, a coin is thrown with velocity "u"=0m/s and time "t"=1.2s,it gains an acceleration due to gravity, then using the formula, $H=ut+\frac{1}{2}gt^{2}$;

Since u=0 and g=9.81, therefore,

$H=\frac{1}{2}(9.81)(1.2)^{2}$

$H=\frac{1}{2}(9.81)(1.44)$

$H=\frac{14.1264}{2}$

$H=7.0632m$