(3/4) / (1/4)...when dividing fractions, " flip " what u r dividing by, then multiply.
3/4 * 4/1 = 12/4 reduces to 3
The first letter because 1•5 = 5. 2•5 equals ten etc
Answer:
32
Step-by-step explanation:
The problem above can be solved by using the <em>multiplication operation</em>.
Given: 400 people
8% of the people with green eyes
Let's solve:
Let x be<em><u> the number of people with green eyes.</u></em>
x = 400 x 8%
x = 400 x (0.08)
x = 32
So, the number of people surveyed with green eyes is 32. The rest of the surveyed people (368) have a different eye color.
Answer:
- 4x² - 13x + 8 = 0
- 4x² - 11x + 5 = 0
- 16x² - 41x + 1 = 0
- x² + 5x + 4 = 0
- x² - 66x + 64 = 0
Step-by-step explanation:
<u>Given</u>
- α and β are roots of 4x²-5x-1=0
<u>Then the sum and product of the roots are:</u>
- α+b = -(-5)/4 = 5/4
- αβ = -1/4
(i) <u>Roots are α + 1 and β + 1, then we have:</u>
- (x - (α + 1))(x - (β + 1)) = 0
- (x - α - 1)(x - β - 1) = 0
- x² - (α+β+2)x + α+β+ αβ + 1 = 0
- x² - (5/4+2)x +5/4 - 1/4 + 1 = 0
- x² - 13/4x + 2= 0
- 4x² - 13x + 8 = 0
(ii) <u>Roots are 2 - α and 2 - β, then we have:</u>
- (x + α - 2)(x + β - 2) = 0
- x² + (a + β - 4)x - 2(α + β) + αβ + 4 = 0
- x² + (5/4 - 4)x - 2(5/4) - 1/4 + 4 = 0
- x² - 11/4x - 10/4 - 1/4 + 16/4 = 0
- x² - 11/4x + 5/4x = 0
- 4x² - 11x + 5 = 0
(iii) <u>Roots are α² and β², then:</u>
- (x - α²)(x-β²) = 0
- x² -(α²+β²)x + (αβ)² = 0
- x² - ((α+β)² - 2αβ)x + (-1/4)² = 0
- x² - ((5/4)² -2(-1/4))x + 1/16 = 0
- x² - ( 25/16 + 1/2)x + 1/16 = 0
- x² - 33/16x + 1/16 = 0
- 16x² - 33x + 1 = 0
(iv) <u>Roots are 1/α and 1/β, then:</u>
- (x - 1/α)(x - 1/β) = 0
- x² - (1/α+1/β)x + 1/αβ = 0
- x² - ((α+β)/αβ)x + 1/αβ = 0
- x² - (5/4)/(-1/4)x - 1/(-1/4) = 0
- x² + 5x + 4 = 0
(v) <u>Roots are 2/α² and 2/β², then:</u>
- (x - 2/α²)(x - 2/β²) = 0
- x² - (2/α² + 2/β²)x + 4/(αβ)² = 0
- x² - 2((α+β)² - 2αβ)/(αβ)²)x + 4/(αβ)² = 0
- x² - 2((5/4)² - 2(-1/4))/(-1/4)²x + 4/(-1/4)² = 0
- x² - 2(25/16 + 8/16)/(1/16)x + 4(16) = 0
- x² - 2(33)x + 64 = 0
- x² - 66x + 64 = 0
Answer:
d
Step-by-step explanation:Angle 12 & 10 are effectively corresponding angles, but angle 10 & 7 are alternate interior angles. Anyways, Angle 12 & 10 are congruent and 10 & 7 are congruent. At the end, the three angles 12, 10, and 7 have the same measure. If we put it otherwise, the line B is intersecting line D which form right angles equals to 90 degrees, so angle 12 = 90, and the same happens with angle 10 and 7, so the three angles are congruent, but at the same time, angle 7 is supplementary with angle 12 because their sum is equal to 180, (90 + 90 = 180). If you think from different angles is hard to choose the right answer, so what I guess is that we don't need to take into account the angle 10, just the fact that line A intersect line C, and Line B intersect line D forming right angles, and that angle 7 and 12 are right angles which sum equals 180, therefore, we could say that they are supplementary angles, but also congruent because they measure the same, so at the end,
