Answer:
Point of intersections are (0, -7) and (5, -2).
Step-by-step explanation:
From the graph attached,
A straight line is intersecting the circle at the two points (0, 7) and (5, -2).
Now solve algebraically,
Equation of the line → y = x - 7 -------(1)
Equation of the circle → (x - 5)² + (y + 7)² = 25 -------(2)
By substituting the value of y from equation (1) to equation (2)
(x - 5)² + (x - 7 + 7)² = 25
(x - 5)² + x² = 25
x² - 10x + 25 + x² = 25
2x² - 10x = 0
x² - 5x = 0
x(x - 5) = 0
x = 0, 5
From equation (1),
y = 0 - 7 = -7
y = 5 - 7 = -2
Therefore, point of intersections are (0, -7) and (5, -2).
No, because BC and BD are not the same lengths. If AB = BC, then AB and BD are not the same lengths -> ABDE is not a rhombus.
Answer:
553 km
Step-by-step explanation:
1:55.3 to 10:553
Answer: a=4, b=-8, c=-3
Step-by-step explanation: This equation isn't in standard form. To get it there, subtract -3 from both sides. This gets you an equation of 4x^2-8x-3.
The standard form is ax^2+bx+c.
A is the number before x^2 (4). B is the number before x, and since it's subtracted it's negative (-8). C is the last number, and since it's subtracted it's negative (-3).
