The answer is (5x+3)/2 . So it’s A .
Answer:
Some answers to the reducing fraction sheet
Q14 = 4/5 because divide 12 and 15 by 3
Q15=can't be reduced because 11 is a prime number so it can't be divided by anything
Q17=can't be reduced because 17 is a prime number
Q18=can't be reduced because 13 is a prime number
Q19=38/9 because 114 and 27 would be divided by 3
Q20= -1/1 because you would divide both 14,529 by itself would equal to - 1/1
I can only help you with this sheet I can't help you with the other one hope this was helpful! :)
Just plug in one of the other (doesn't matter which one) so it will look like
-3x+6=5x+38
or
5x+38=-3x+6 (it's the same thing as the first one)
Then you solve for x and you substitute that value so you can get y.
Hope this helped :)
The class which generally had the highest pulse of students recorded by the science teacher after climbing the stairs is class 3.
<h3>What is box plot representation of data?</h3>
Box plot is the way of representation of data which gives the graphical image of the data set to understand better.
The minimum and the maximum values in the box plot is plotted at the end points.
- A science teacher recorded the pulse of each of the students in her classes after the students had climbed a set of stairs.
- She displayed the results, by class, using the box plots shown.
In this box plot, the class 3 has the highest value compare to all the box plot.
Thus, the class which generally had the highest pulse of students recorded by the science teacher after climbing the stairs is class 3.
Learn more about the box plot here;
brainly.com/question/14277132
#SPJ1
Answer:
In a certain Algebra 2 class of 30 students, 22 of them play basketball and 18 of them play baseball. There are 3 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
I know how to calculate the probability of students play both basketball and baseball which is 1330 because 22+18+3=43 and 43−30 will give you the number of students plays both sports.
But how would you find the probability using the formula P(A∩B)=P(A)×p(B)?
Thank you for all of the help.
That formula only works if events A (play basketball) and B (play baseball) are independent, but they are not in this case, since out of the 18 players that play baseball, 13 play basketball, and hence P(A|B)=1318<2230=P(A) (in other words: one who plays basketball is less likely to play basketball as well in comparison to someone who does not play baseball, i.e. playing baseball and playing basketball are negatively (or inversely) correlated)
So: the two events are not independent, and so that formula doesn't work.
Fortunately, a formula that does work (always!) is:
P(A∪B)=P(A)+P(B)−P(A∩B)
Hence:
P(A∩B)=P(A)+P(B)−P(A∪B)=2230+1830−2730=1330
