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2 years ago

15

A movie rental website charges $5.00 per month for membership and $1.25 per movie.Melissa has $18.50 this month to spend on movi

e rentals.How many movies can she view this month?Tell how u did it or it won't count

2 answers:

irina [24]2 years ago

7 0

She can only but 14 movies because 18.50÷1.25= 14.8 and then 1.25×14=17.5

user100 [1]2 years ago

4 0

She can only view 10. To get this answer, you subtract the $5.00 for membership from the $18.50 of her total amount. You then get $13.50. Then, you divide $13.50 (the money she has left) by $1.25 (the amount of money each movie costs). Your answer is 10.8, but you can't have 10.8 movies, so you have to round down to ten. She <u>cannot</u> view 11 because she does not have enough money. <em></em>Hopefully this helps you!!!<em />

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60 pizzas

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3 years ago

The sides of a rhombus with angle of 60° are 6 inches. Find the area of the rhombus.

ehidna [41]

1. Check the drawing of the rhombus ABCD in the picture attached.

2. m(CDA)=60°, and AC and BD be the diagonals and let their intersection point be O.

3. The diagonals:
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ii) are perpendicular to each other, so m(DOC)=90°

4. In a right triangle, the length of the side opposite to the 30° angle is half of the hypothenuse, so OC=3 in.

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6. The 4 triangles formed by the diagonal are congruent, so the area of the rhombus ABCD = 4 Area (triangle DOC)=4* $\frac{DO*OC}{2}=4 \frac{3 \sqrt{3} *3}{2}$ = $=2*9 \sqrt{3}=18 \sqrt{3}$ ( $in^{2}$ )

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2 years ago

How to make this a simultaneous equation?

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Hello,

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2 years ago

Dwayne drove 18 miles to the airport to pick up his father and then returned home. On the return trip he was able to drive an av

Nesterboy [21]

Answer:

30 mph

Step-by-step explanation:

Let d = distance (in miles)

Let t = time (in hours)

Let v = average speed driving <u>to</u> the airport (in mph)

⇒ v + 15 = average speed driving <u>from</u> the airport (in mph)

Using: distance = speed x time

$\implies t=\dfrac{d}{v}$

Create two equations for the journey to and from the airport, given that the distance one way is 18 miles:

$\implies t=\dfrac{18}{v} \ \ \textsf{and} \ \ t=\dfrac{18}{v+15}$

We are told that the total driving time is 1 hour, so the sum of these expressions equals 1 hour:

$\implies \dfrac{18}{v} +\dfrac{18}{v+15}=1$

Now all we have to do is solve the equation for v:

$\implies \dfrac{18(v+15)}{v(v+15)} +\dfrac{18v}{v(v+15)}=1$

$\implies \dfrac{18(v+15)+18v}{v(v+15)}=1$

$\implies 18(v+15)+18v=v(v+15)$

$\implies 18v+270+18v=v^2+15v$

$\implies v^2-21v-270=0$

$\implies (v-30)(v+9)=0$

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As v is positive, v = 30 only

So the average speed driving to the airport was 30 mph

(and the average speed driving from the airport was 45 mph)

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1 year ago

Read 2 more answers

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GuDViN [60]

Answer:

$P = 0.1447$

Step-by-step explanation:

Given

$n = 7000$ -- total

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Required

The probability of rejecting the batch

This means that at least one of the selected piece is defected.

So, we first calculate the probability that all the selected piece are accepted.

So, we have:

$Pr = \frac{7000 - 180}{7000} * \frac{6999 - 180}{6999}* \frac{6998 - 180}{6998}* \frac{6997 - 180}{6997}* \frac{6996 - 180}{6996}* \frac{6995 - 180}{6995}$

The denominator decreases by 1 because it is a probability without replacement; 180 is subtracted from the numerator to represent the number of non-defective CDs

So, we have:

$Pr = \frac{6820}{7000} * \frac{6819}{6999}* \frac{6818}{6998}* \frac{6817}{6997}* \frac{6816}{6996}* \frac{6815}{6995}$

$Pr = 0.8553$

Using the complement rule, the probability that the batch will be rejected is:

$P = 1 - 0.8553$

$P = 0.1447$

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2 years ago