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3 years ago

14

Devaughn is 5 years older than Sydney. The sum of their age is 87. What is Sydney’s age?

1 answer:

sp2606 [1]3 years ago

3 0

41

87=41+46

I don’t know how the person before me got 56 because 56+61=117

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39. The ratio of new houses to antique houses in a village is 4:5. If there are

jeyben [28]

Step-by-step explanation:

☄ $\underline{ \underline{ \text{Question }}}:$ The ratio of new houses to antique houses in a village is 4 : 5 . If there are 12 new houses , how many antique houses are there ?

☄ $\underline{ \underline{ \text{Solution}}} :$

✏ Let , the number of antique houses in a village be ' x ' .

Then , According to the question :

$\sf{ \frac{Number \: of \: new \: houses}{Number \: of \: antique \: houses} \: = \: \frac{4}{5}}$

⤑ $\sf{ \frac{12}{x} = \frac{4}{5}}$

Apply cross product property

⤑ $\sf{4 \times x = 12 \times 5}$

⤑ $\sf{4x = 60}$

⤑ $\sf{ \frac{4x}{4} = \frac{60}{4}}$

⤑ $\sf{x = 15}$

So, The number of antique houses in a village is 15.

$\red{ \boxed{ \boxed{ \tt{Our \: final \: answer : \boxed{ \bold{15}}}}}}$

Hope I helped ! ♡

Have a wonderful day / night ツ

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7 0

2 years ago

PLEASE HELP WILL MARK BRAINLIEST!

pantera1 [17]

Answer:

Make a coordinate plane and you have to solve around the origin say 4,4 and 4,1.

Step-by-step explanation:

8 0

3 years ago

Sergio is s years old. which expression shows how old he will be 7 years from now? question 5 options: 7s 7 – s s 7 7s 7

notsponge [240]

S+7. Tell your teacher never to use s as a variable ever again.

8 0

2 years ago

Fine length of BC on the following photo.

MrMuchimi

Answer:

$BC=4\sqrt{5}\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

$AC^2=AD^2+DC^2$

substitute the given values

$AC^2=16^2+8^2$

$AC^2=320$

$AC=\sqrt{320}\ units$

simplify

$AC=8\sqrt{5}\ units$

step 2

In the right triangle ACD

Find the cosine of angle CAD

$cos(\angle CAD)=\frac{AD}{AC}$

substitute the given values

$cos(\angle CAD)=\frac{16}{8\sqrt{5}}$

$cos(\angle CAD)=\frac{2}{\sqrt{5}}$ ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

$cos(\angle BAC)=\frac{AC}{AB}$

substitute the given values

$cos(\angle BAC)=\frac{8\sqrt{5}}{16+x}$ ----> equation B

step 4

Find the value of x

In this problem

$\angle CAD=\angle BAC$ ----> is the same angle

so

equate equation A and equation B

$\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}$

solve for x

Multiply in cross

$(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units$

$DB=4\ units$

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

$BC^2=DC^2+DB^2$

substitute the given values

$BC^2=8^2+4^2$

$BC^2=80$

$BC=\sqrt{80}\ units$

simplify

$BC=4\sqrt{5}\ units$

7 0

2 years ago

Solve each equation t-2.7 =23.5

kiruha [24]

You do inverse op 2.7+23.5=26.2

6 0

3 years ago

Read 2 more answers