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nirvana33 [79]
4 years ago
14

Solve for x in the equation x squared + 2 x + 1 = 17.

Mathematics
2 answers:
algol [13]4 years ago
8 0

Answer:

Option B.

Step-by-step explanation:

The given equation is

x^2+2x+1=17

Subtract both sides by 17.

x^2+2x+1-17=17-17

x^2+2x-16=0          .... (1)

If a quadratic equation is ax^2+bx+c=0, then by quadratic formula

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

In equation (1), a=1, b=2 and c=-16. Using quadratic formula we get

x=\dfrac{-(2)\pm \sqrt{(2)^2-4(1)(-16)}}{2(1)}

x=\dfrac{-2\pm \sqrt{4+64}}{2}

x=\dfrac{-2\pm \sqrt{68}}{2}

x=\dfrac{-2\pm 2\sqrt{17}}{2}

Taking out common factors.

x=\dfrac{2(-1\pm \sqrt{17})}{2}

x=-1\pm \sqrt{17}

Therefore, the correct option is B.

dangina [55]4 years ago
3 0

Answer:

The answer to your question is the second option

Step-by-step explanation:

Process

1.- Write the equation

                                 x² + 2x + 1 = 17

Factor the first term

                                 (x + 1)² = 17

Get the square root

                                 \sqrt{(x+1)^{2} }  = \sqrt{17}

                                 (x + 1) = \sqrt{17}

Result

                                x₁ = - 1 + \sqrt{17}

                                 x₂ = -1  - \sqrt{17}                                

                               

                                 

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