Moshe has the container shown below on his desk to hold pencils and paper clips. 2 rectangular prisms. One has a length of 4 inc
2 answers:
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Answer:
a. p=1.000
b. p=0.2924
c. p=0.7358
d. No
Step-by-step explanation:
a. This problem satisfies all the criteria for a binomial experiment expressed as:
-Given that p=0.85, n=14, the probability that exactly all 14 were on time is calculated as:
Hence, the probability that all 12 flights are on time is 1.0000
b. Given that n=12, and p=0.85
-The probability that exactly 10 flights are on time is calculated as;
Hence, the probability that exactly 10 flights are on time is 0.2924
c. Given that n=12, and p=0.85
-The probability that more of 10 or more flights are on time:
Hence, the probability of 10+ flights being on time is 0.7358
d. We first find the mean of the distribution:
#We then find the probability of 11+=0.3012+0.1422=0.4434
-We compare the expectation to the probability of 11+ flights being on time.
No. Since the probability =0.4434 < that the expectation, 11.9, it is not unusual for 11+ flights to be on time.
*I have used a sample size of n=12 since there are two separate n values: