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Furkat [3]
3 years ago
15

I don’t know to how to put this in the format they want it

Mathematics
1 answer:
worty [1.4K]3 years ago
7 0

For this case, we decompose 240 into prime factors:

So, we have:

240 divided by 2

120 divided by 2

60 divided by 2

30 divided by 2

15 divided by 3

5 divided by 5

one

So, we have to, according to the right side of the decomposition shown:

240 = 2 * 2 * 2 * 2 * 3 * 5 = 2 ^ 4 * 3 * 5

Answer:

240 = 2 ^ 4 * 3 * 5

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A CARPENTER SAWED A PIECE OF WOOD INTO 3 PIECES. THE RATIO OF WOOD PIECES IS 1:3:6. THE LONGEST PIECE IS 2.5 FEET LONGER THAN TH
IgorLugansk [536]
1 : 3 : 6

longest piece is 2.5 longer than the shortest piece.

let x be the shortest piece.

x + 2.5 is the longest piece

x/10 + 3/10 + (x+2.5)/10 = 1
x + 3 + x + 2.5 / 10 = 1
2x + 5.5 = 10
2x = 10 - 5.5
2x = 4.5
x = 4.5/2
x = 2.25  shortest piece.

x + 2.5 = 2.25 + 2.5 = 4.75 longest piece.

ratio of the 2nd piece to the 3rd piece is 3:6
2nd piece is half of the 3rd piece

4.75 x 1/2 = 2.375

1 : 3 : 6
2.25 : 2.375 : 4.75


8 0
4 years ago
Read 2 more answers
Please help fast
beks73 [17]
You are given that PS ≅ RS as indicated by the single has mark.

You are given that ∠PST ≅ ∠RST as indicated by the single arc.

You know the segment ST is congruent to itself by the reflexive property.

That is, you have two congruent sides and the angle between them, so you can claim the triangles are congruent by the SAS postulate.

Selection C is appropriate.
3 0
3 years ago
Read 2 more answers
According to an​ airline, flights on a certain route are on time 8080​% of the time. Suppose 1111 flights are randomly selected
Sergio [31]

Answer:

a. This experiment satisfy the conditions below.

b. 0

c. 0

d. 1

e. 0

Step-by-step explanation:

a. This experiment satisfy the following conditions:

1. The experiment consists of n = 1111 identical trials, i.e., to determine if each flight is on-time or not.

2. Each trial results in success or failure, i.e., the flight is on-time or not.

3. The probability of success in each trial is the same, p = 0.8, because a flight is on-time 80% of the time.

4. The trials are independent because the 1111 flights were selected randomly.

5. Te random variable of interest is Y, the number of on-time flights observed in the n = 1111 flights.

b. P(Y = 99) = \frac{1111!}{99!(1111-99)!}(0.8)^99(0.2)^{1111-99} = 0. This is the probability that 99 flights are on time and 1012 are not.

c. P(Y < 99) = \sum_{i=1}^{98}\frac{1111!}{y!(1111-y)!}(0.8)^y(0.2)^{1111-y} = 0. This is the probability that 0 flights are on-time or 1 flight is on-time or ... or 98 flights are on-time.

d. 1 - P(Y < 99) = 1 - 0 = 1. This is the probability that 99 flights are on-time or 100 flights are on-time or ... or all 1111 flights are on-time.

e. P(77\leq Y \leq 99) = \sum_{i=77}^{99}\frac{1111!}{y!(1111-y)!}(0.8)^y(0.2)^{1111-y} = 0 This is the probability that 77  flights are on-time or 78 flights are on-time or ... or 99 flights are on-time.

8 0
3 years ago
I need help with this hard question
DedPeter [7]

Answer:

Bottom left = 8

Top right = 15

Middle right = 25

Step-by-step explanation:

Total = 40

3 + 5 = 8

40 / 8 = 5

1 part = 5

5 x 3 = 15

5² = 25

6 0
2 years ago
Bart uses 3/12 cup milk to make muffins. Write a fraction that is equivalent to 3/12 pls help out!
maks197457 [2]

Answer:

1/4

Step-by-step explanation:

4 0
3 years ago
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